Explanation:
Given:
v₀ = 0 m/s
a = 2.50 m/s²
t = 4 s
Find: v
v = at + v₀
v = (2.50 m/s²) (4 s) + 0 m/s
v = 10 m/s
<span>I believe this question has additional detail which stated
that during the 1st half, his speed was 2.01 m/s. From this we can
calculate his speed during the second half, v2, using the formula:</span>
v_ave = (v1 + v2) / 2
2.05 m/s = (2.01 m/s + v2) / 2
<span>v2 = 2.09 m/s</span>
Given :
The temperature of 10 kg of a substance rises by 55oC when heated.
To Find :
The temperature rise when 22 kg of the substance is heated with the same quantity of heat.
Solution :
We know, change in temperature when heat is given to object is given by :
It is given that same amount of heat is given in both the cases also the substance is same.
So,
Hence, this is the required solution.
hello!
your answer is
D) elimination-by-aspects model!
have a nice day :D
Answer:
340 W
Explanation:
Power = change in energy / change in time
P = ΔKE / Δt
P = ½ mv² / Δt
P = ½ (90 kg) (15 m/s)² / (30 s)
P = 337.5 W
Rounded to 2 significant figures, the power is 340 W.
