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sleet_krkn [62]
2 years ago
11

Multiply: (2sin B+cos B)by 3cosec B.secB​

Mathematics
1 answer:
adoni [48]2 years ago
6 0

Step-by-step explanation:

Is this the full question

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What is the general rule for the sequence?<br> 1.11, 2.54, 3.97, 5.40, ...
mina [271]
The pattern is adding 1.43 to the term before

1.11 + 1.43 = 2.54 + 1.43 = 3.97 + 1.43 = 5.40 . . .and so on.


7 0
3 years ago
Read 2 more answers
Marcus wants to buy a PS5 and some digital games. The console cost $725 and he plans to buy games that cost $45. He only has $98
wariber [46]
I don’t know your question sooo I’m just going to go based on what I know.

980 - 725 = 225
$225 is how much you have left to buy games

In the end you can only buy about 3 games with $40 left
7 0
3 years ago
If (2i/2+i)-(3i/3+i)=a+bi, then a=<br>A. 1/10<br>B. -10<br>C. 1/50<br>D. -1/10​
Verizon [17]

Answer:

Option A is correct.

Step-by-step explanation:

We are given:

\frac{2i}{2+i}-\frac{3i}{3+i} = a+bi

We need to find the value of a.

The LCM of (2+i) and (3+i)  is (2+i)(3+i)

=\frac{2i(3+i)}{(2+i)(3+i)}-\frac{3i(2+i)}{(2+i)(3+i)}\\=\frac{6i+2i^2}{(2+i)(3+i)}-\frac{6i+3i^2}{(2+i)(3+i)}\\=\frac{6i+2i^2-(6i+3i^2)}{(2+i)(3+i)}\\=\frac{6i+2i^2-6i-3i^2)}{5+5i}\\=\frac{-i^2}{5+5i}\\i^2=-1\\=\frac{-(-1)}{5+5i}\\=\frac{1}{5+5i}

Now rationalize the denominator by multiplying by 5-5i/5-5i

=\frac{1}{5+5i}*\frac{5-5i}{5-5i} \\=\frac{5-5i}{(5+5i)(5-5i)}\\=\frac{5-5i}{(5+5i)(5-5i)}\\(a+b)(a-b)= a^2-b^2\\=\frac{5(1-i)}{(5)^2-(5i)^2}\\=\frac{5(1-i)}{25+25}\\=\frac{5(1-i)}{50}\\=\frac{1-i}{10}\\=\frac{1}{10}-\frac{i}{10}

We are given

\frac{2i}{2+i}-\frac{3i}{3+i} = a+bi

Now after solving we have:

\frac{1}{10}-\frac{i}{10}=a+bi

So value of a = 1/10 and value of b = -1/10

So, Option A is correct.

8 0
3 years ago
Please help Last Question!!!
pshichka [43]

Answer:

  24%

Step-by-step explanation:

2610 of the 10730 students are graduates. The probability of choosing a graduate at random from all students is ...

  2610/10730 × 100% ≈ 24.324% ≈ 24%

8 0
2 years ago
What point is a solution to y&gt; 2x -1<br><br> A.(0,2)<br> B.(4,2)<br> C.(0,-10)<br> D.(4,1)
Tom [10]

Well, we need to consider the x and y coordinates of the giben points, and check wether the y coordinate is greater than twice the x coordinate minus 1 (i.e. 2x-1):

  • For the first point, the x coordinate is 0. So, 2x-1 = -1. The y coordinate is 2, and 2>-1. So, this point is a solution.
  • For the second point, the x coordinate is 4. So, 2x-1 = 7. The y coordinate is 2, and 2<7. So, this point is not a solution.
  • For the third point, the x coordinate is 0. So, 2x-1 = -1. The y coordinate is -10, and -10<-1. So, this point is not a solution.
  • For the fourth point, the x coordinate is 4. So, 2x-1 = 7. The y coordinate is 1, and 1<7. So, this point is not a solution.
4 0
2 years ago
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