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Igoryamba
3 years ago
10

Find the solutions of x^2+30 = 0 please give detailed steps!

Mathematics
1 answer:
murzikaleks [220]3 years ago
6 0

Answer:

x= <em>i</em>√30

Step-by-step explanation:

<u>I'm going to go into this under the assumption that you've covered imaginary numbers based on the </u><u>question.</u><u> If I'm wrong then sorry about that.</u>

Okay, so first you want to subtract 30 from both sides

x^2=-30

Then you take the square root of each side.

√(x^2)=√-30

x=√-30

Since it's impossible to square a number to get a negative number, you'll end up with an imaginary number. You have to rewrite x=√-30 to get rid of the negative sign under the radical. Rewriting this will also indicate that it's an imaginary number.

<u>Final</u><u> </u><u>answer</u><u>:</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>i√30</u>

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What are the factors of 7x + 5x + 12 + 23
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
Which set of ordered pairs does not represent a function? \{(5, -9), (6, -6), (-3, 8), (9, -6)\}{(5,−9),(6,−6),(−3,8),(9,−6)} \{
Nady [450]

Answer:

\{(-6, -4), (4, -8), (-6, 9), (1, -3)\}

Step-by-step explanation:

Given

\{(5, -9), (6, -6), (-3, 8), (9, -6)\}

\{(-6, -4), (4, -8), (-6, 9), (1, -3)\}

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\{(8, -9), (-3, -6), (-4, 4), (1, -5)\}

Required

Which is not a function

An ordered pair is represented as:

\{(x_1,y_1),(x_2,y_2),(x_3,y_3),..........,(x_n,y_n)\}

However, for the ordered pair to be a function; all the x values must be unique (i.e. not repeated)

<em>From options (a) to (d), option (b) has -6 repeated twice. Hence, it is not a function.</em>

4 0
2 years ago
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Answer:

  C.  2(k +2)(k +5)(k +1)

Step-by-step explanation:

The LCM will be the product of unique factors.

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The unique factors are 2, (k+1), (k+2), (k+5), so the LCM is their product:

  2(k+1)(k+2)(k+5) . . . . matches choice C

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