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3 years ago

8

Which of the following is a measure of velocity?

1 answer:

Cloud [144]3 years ago

3 0

The definition of velocity is a speed in a given direction. So the unit must include the speed and the direction that the object is moving. C. 31 m/s north is the correct answer, because the unit has the speed and the distance included. Although D has the same factors in it's answer, speed is only distance divided by time, and is not squared as it is shown incorrectly in answer D.

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An air conditioner operating at steady state maintains a dwelling at 70oF on a day when the outside temperature is 90oF. If the

torisob [31]

30000 btuh /3413 btuh/kw. = 8.8 kw

8.8 kw/.746 kw/hp = 11.8 hp if COP is 1

11.8/3 hp (COP coefficient of performance) = 3.99 COP

>>>So yes a 3.0 hp compressor with a nominal COP of 4 will handle the 30,000 btuh load.

3.2 to 4.5 is expected COP range for an air cooled heat pump or a/c unit.

8 0

3 years ago

What are the differences between refraction and diffraction?

Liula [17]

Refraction is the change in direction of a wave.
Diffraction is the bending of a wave around a barrier.

5 0

3 years ago

A rectangular block of copper metal weighs 1896 g. The dimensions of the block are 8.4 cm by 5.5 cm by 4.6 cm. From this data, w

sp2606 [1]

Answer:

8.9 g/cm^3

Explanation:

density = mass/volume

volume = length * width * height

volume = (8.4 cm)(5.5 cm)(4.6 cm)

volume = 212.52 cm^3

mass = 1896 g

density = (1896 g)/(212.52 cm^3)

density = 8.9 g/cm^3

3 0

3 years ago

Consider an oil droplet of mass m and charge q. We want to determine the charge on the droplet in a Millikan-type experiment. We

Katen [24]

Answer:

$q=\frac{mg}{E_o}$

Explanation:

Given:

Charge = <em>q</em>

Electric field strength = $E_o$

weight of the droplet = <em>mg</em>

The charge is suspended motionless. This is because the electric force on the charge is balanced by the weight of the droplet.

electric force on charged droplet, $F=qE_o$

This is balanced by the weight, $mg$

Equating the two:

$qE_o=mg\\\Rightarrow q=\frac{mg}{E_o}$

4 0

3 years ago

Predict using Boyle's law, what will happen to a balloon that an ocean diver takes to a pressure of 202 kPa.

kobusy [5.1K]

The volume of the balloon will halve

Explanation:

Boyle's law states that for an ideal gas kept at constant temperature, the pressure of the gas is proportional to its volume. Mathematically,

$pV=const.$

where

p is the gas pressure

V is the volume

The equation can also be rewritten as

$p_1 V_1 = p_2 V_2$

And if we apply it to the gas inside the balloon in this problem (assuming its temperature is constant), we have:

$p_1 = 101 kPa$ is the initial pressure at sea level (the atmospheric pressure)

$V_1$ is the initial volume

$p_2 = 202 kPa$ is the final pressure

$V_2$ is the final volume

Substituting into the equation, we find:

$V_2 = \frac{p_1 V_1}{p_2}=\frac{(101)V_1}{202}=\frac{V_1}{2}$

Which means that the volume of the balloon will halve.

Learn more about ideal gases:

brainly.com/question/9321544

brainly.com/question/7316997

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#LearnwithBrainly

6 0

3 years ago