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azamat
3 years ago
10

A rectangular block of copper metal weighs 1896 g. The dimensions of the block are 8.4 cm by 5.5 cm by 4.6 cm. From this data, w

hat is the density of copper? (hint: find the volume of a block first)
Physics
1 answer:
sp2606 [1]3 years ago
3 0

Answer:

8.9 g/cm^3

Explanation:

density = mass/volume

volume = length * width * height

volume = (8.4 cm)(5.5 cm)(4.6 cm)

volume = 212.52 cm^3

mass = 1896 g

density = (1896 g)/(212.52 cm^3)

density = 8.9 g/cm^3

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A _ system is one in which one subsystem provides services to another subsystem.
astra-53 [7]

Answer:

u

Explanation:

o

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2 years ago
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If the mercury barometer is 75.58 cm at the base of the mountain and 66.37 cm at the summit. What is the height of the mountain?
Licemer1 [7]

Answer:

5016.2446

Explanation:

3 0
3 years ago
A disc with a mass of 1 kg moves horizontally to the right with a speed of 7 m/s on a table with negligible friction when it col
Elodia [21]

Answer:

1.6 m/s

Explanation:

First you need to find the momentums of each disc by multiplying their velocities with mass.

disc 1: 7*1= 7 kg m/s

disc 2: 1*9= 9 kg m/s

Second, you need to find the total momentum of the system by adding the momentums of each sphere.

9+7= 16 kg m/s

Because momentum is conserved, this is equal to the momentum of the composite body.

Finally, to find the composite body's velocity, divide its total momentum by its mass. This is because mass*velocity=momentum

16/10=1.6

The velocity of the composite body is 1.6 m/s.

7 0
2 years ago
On a popular amusement park ride, the riders stand along the inside wall of a large cylinder with a diameter of 8.27 m. The cyli
____ [38]

Answer:

Explanation:

D = 8.27 m   ⇒  R = D / 2 = 8.27 m / 2 = 4.135 m

ω = 0.66 rev/sec = (0.66 rev/sec)*(2π rad/1 rev) = 4.1469 rad/s

We can apply the equation

Ff = W  ⇒  μ*N = m*g   <em>(I)</em>

then we have

N = Fc = m*ac = m*(ω²*R)

Returning to the equation <em>I</em>

<em />

μ*N = m*g    ⇒    μ*m*ω²*R = m*g   ⇒ μ = g / (ω²*R)

Finally

μ = (9.81 m/s²) / ((4.1469 rad/s)²*4.135 m) = 0.1379

3 0
3 years ago
A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 146 cm and makes an angl
svetlana [45]

Answer:

B = 191.26 cm

θ = -14.73°

Explanation:

given,

magnitude of the first displacement(A) = 146 cm

at an angle of 124°

resultant magnitude = 137 cm

and angle made with x-axis by the resultant(R) = 32.0°

component of A in X and Y direction

A x = A cos θ  = 146 cos 120° = -73 cm

A y = A sin θ = 146 sin 120° = 126.4 cm

now component of resultant in x and y direction

R x = 137 cos 35°

    = 112.2 cm

R y = 137 sin 35°

     = 78.6 cm

resultant is the sum of two vectors

R = A + B

R x = A x + B x

B x =  112.2 - (-73) = 185.2 cm

B y = R y - A y

B y = 78.6 - 126.4 = -47.8 cm

magnitude of B

B = \sqrt{B_x^2+B_y^2}

B = \sqrt{185.2^2+-47.8^2}

B = 191.26 cm

angle\theta = tan^{-1}\dfrac{-47.8}{185.2}

θ = -14.73°

6 0
3 years ago
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