Answer: pH = 10
Explanation: First solve for pOH using the equation pOH=-log[OH-] = 4
Then plug the pOH in the equation, pH + pOH =14
then solve for pH. pH =14 - 4 = 10
<u>Answer:</u> The molarity of saline solution is 0.909 M
<u>Explanation:</u>
We are given:
5.21 w/w % NaCl
This means that 5.21 grams of NaCl is present in 100 grams of solution
To calculate mass of a substance, we use the equation:

Density of solution = 1.02 g/mL
Mass of solution = 100 g
Putting values in above equation, we get:

To calculate the moalrity of solution, we use the equation:

Given mass of NaCl = 5.21 g
Molar mass of NaCl = 58.44 g/mol
Volume of solution = 98.04 mL
Putting values in above equation, we get:

Hence, the molarity of saline solution is 0.909 M
Hydrogen bonds.
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Answer:
The final pressure will double i.e it will be twice the initial pressure
Explanation:
T1 = T
T2 = 2T ( twice the original T)
P1 = P
P2 =?
Since the volume is constant,
P1/ T1 = P2 /T2
P/ T = P2 / 2T
Cross multiply
T x P2 = 2T x P
Divide both side by T
P2 = (2T x P) / T
P2 = 2P
Therefore, the final pressure will double i.e it will be twice the initial pressure