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kupik [55]
3 years ago
15

The rate of diffusion of gas A is double the rate of gas B. The ratio of their molecular weight is​

Chemistry
1 answer:
Dafna1 [17]3 years ago
4 0

Answer:

Ratio is 4:1

Explanation:

from graham's law of gaseous diffusion:

{ \bf{ \frac{R _{A} }{R_{B} }  =  \sqrt{ \frac{M_{A} }{M_{B}} } }}

but Ra = 2Rb:

{ \sf{ (\frac{2}{1} ) {}^{2}   =  \frac{M _{A}}{M _{B} }   }} \\  \\ { \sf{\frac{M _{A}}{M _{B} } =  \frac{4}{1} }} \\  \\ {M _{A}} : {M _{B} } = 4 :1

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A 500 mL hypertonic saline solution is labeled as consisting of 5.21 % w/w NaCl. Given that the density of salt water is 1.02 g/
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<u>Answer:</u> The molarity of saline solution is 0.909 M

<u>Explanation:</u>

We are given:

5.21 w/w % NaCl

This means that 5.21 grams of NaCl is present in 100 grams of solution

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Putting values in above equation, we get:

1.02g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.02g/mL}=98.04mL

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\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

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\text{Molarity of solution}=\frac{5.21\times 1000}{58.44g/mol\times 98.04}\\\\\text{Molarity of solution}=0.909M

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The chemical equation of photosynthesis includes 6O2. What does the small number after the O represent?
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If a gas’s [kelvin] temperature doubles and it’s volume then remains the same, then what happens to it’s pressure?
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Answer:

The final pressure will double i.e it will be twice the initial pressure

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Since the volume is constant,

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