A drop of indicator solution is added to the titration at the start; when the color changes the endpoint has been reached.
Missing in your question the K constant value =2.99X10^-7
The reaction equation:
SOCl2 ⇄ SO2 +Cl2
initial 0.195 0 0
-X +X +X
final (0.195-X) X X
K= [SO2][Cl2]/SOCl2
by substitution
2.99X10^-7 = (X)(X)/(0.195-X)
2.99X10^-7 = X^2 / (0.195-X) by solving this equation
∴X = 0.00024 = 2.4 X10^-4
∴[Cl2] = 2.4X10^-4 m
Answer:
E. 1.5M
Explanation:
because there is total 175.32 g of NaCl dissolved in 2 liter of water, and 58.44 g = 1 mol
so total miles = 175.32/58.32 = 3 moles
now 3 moles are in 2 liter of water, hence one liter contains 3/2= 1.5
Therefore answer is E. 1.5M
Zn (s) -> Zn+2 (aq) + 2e-
Zn (s) with a neutral charge is oxidized and looses two electrons in the process to form ZnCl2 (aq) where Zn has a charge of 2+.
B. Low blood pressure and drooling. If the user is tranquilized, he would not be able to hinder the production of saliva, leading to drooling. And if the victim was tranquilized, his heart would slow down, not speed up, resulting in a lower blood pressure.
