Answer:
100.4mL
Explanation:
Using the following formula:
C1V1 = C2V2
Where;
C1 = initial concentration (M)
C2 = final concentration (M)
V1 = initial volume (mL)
V2 = final volume (mL)
According to the information in this question,
C1 = 1.50M
V1 = ?
C2 = 9.65 M
V2 = 15.6 mL
Using C1V1 = C2V2
V1 = C2V2/C1
V1 = (9.65 × 15.6) ÷ 1.5
V1 = 150.54 ÷ 1.5
V1 = 100.36 mL
Approximately, V1 = 100.4mL
Because the suffix is -ene. Anything that ends in ene is an alkene.
Answer:
a. Lead (Pb)
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Answer is: her reasoning is flawed, because <span>Kc is very small, so the concentration of nitric(II) oxide is also very small. </span>
Balanced chemical reaction: N₂(g) + O₂(g) ⇄<span> 2NO(g).
</span>The equilibrium
constant<span> (Kc) is
a ratio of the concentration of the products (in this reaction nitrogen(II) oxide) to the concentration of the reactants (in this reaction nitrogen and oxygen):
</span>Kc = [NO]² / [N₂] · [O₂].
Kc = 4.7·10⁻³¹.
If we take equilibrium concentration of oxygen and nitrogen to be 1 M:
[N₂] = [O₂] = 1 M.
[NO] = √[N₂] · [O₂] · Kc.
[NO] = 6.855·10⁻¹⁶ M; equilibrium concentration of nitric oxide.
