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4 years ago

10

Consider a point located equidistant from point charges A and B, labeled C in the diagram. If A and B have the same magnitude ch

arge, but A is positive and B is negative, which way does the electric field vector point at C
a) up
b) down
c) right
d) left

1 answer:

klio [65]4 years ago

4 0

I'm pretty sure its' A. up, Hope this helps :)

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You hang a heavy ball with a mass of 10 kg from a gold wire 2.6 m long that is 1.6 mm in diameter. You measure the stretch of th

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<u>Answer:</u> The Young's modulus for the wire is $6.378\times 10^{10}N/m^2$

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Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.

The equation representing Young's Modulus is:

$Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}$

where,

Y = Young's Modulus

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Putting values in above equation, we get:

$Y=\frac{10\times 9.81\times 2.6}{(3.14\times (8\times 10^{-4})^2)\times 1.99\times 10^{-3}}\\\\Y=6.378\times 10^{10}N/m^2$

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