Answer:
9.91 mL
Explanation:
Using the combined gas law equation as follows;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (torr)
P2 = final pressure (torr)
V1 = initial volume (mL)
V2 = final volume (mL)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question;
V1 = 15.0mL
V2 = ?
P1 = 760 torr
P2 = 1252 torr
T1 = 10°C = 10 + 273 = 283K
T2 = 35°C = 35 + 273 = 308K
Using P1V1/T1 = P2V2/T2
760 × 15/283 = 1252 × V2/308
11400/283 = 1252V2/308
Cross multiply
11400 × 308 = 283 × 1252V2
3511200 = 354316V2
V2 = 3511200 ÷ 354316
V2 = 9.91 mL
Your answer would be D. As the circulatory system pumps oxygen rich blood through the body, and the respiratory system helps you to breath. Hope this helps!
The one that has a higher entropy for the reaction is products.
<h3>What is entropy?</h3>
Entropy is a measureable physical characteristic and a scientific notion that is frequently connected to a condition of disorder, unpredictability, or uncertainty. It is the measurement of the amount of thermal energy per unit of temperature in a system that cannot be used for productive work. It is a measure of a system's molecular disorder or unpredictability since work is produced by organized molecular motion.
It should bm be noted that the entropy of gas is more than entropy of aqueous which is more than the entropy of liquid and the entropy of solid.
On the product side there are more gas than the reactant side. Therefore, product has more entropy.
Learn more about entropy on:
brainly.com/question/6364271
#SPJ1
Answer:
Mass of P4O6=103.4
P4O10=133.48
Explanation:
Balanced reaction is:
8P +8
⇒
+
Both reactant completely vanishes as equivalent of bot are equal.
Moles of P=
=3.80
Moles of = =3.80
No. of moles of formed product are equal and is 
th of mole of any of reactant.
Thus weight of =
×220 ≈103.41
weight of =×284 ≈133.48
Answer:
The answer to your question is ΔH° rxn = -1343.9 kJ/mol
Explanation:
P₄O₆ (s) + 2 O₂ (g) ⇒ P₄O₁₀
ΔH°rxn = ?
Formula
ΔH°rxn = ∑H° products - ∑H° reactants
H° P₄O₆ = -1640.1 kJ/mol
H° O₂ = 0 kJ/mol
H° P₄O₁₀ = -2984 kJ/mol
-Substitution
ΔH° rxn = (-2984) - (-1640.1) - (0)
-Simplification
ΔH° rxn = -2984 + 1640.1
ΔH° rxn = -1343.9 kJ/mol
