What is the magnitude of the electric field at a point 0.0055 m from a 0.0025
1 answer:
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Answer:
Change in momentum is 1.1275 kg-m/s
Explanation:
It is given that,
Mass of the ball, m = 274 g = 0.274 kg
It hits the floor and rebounds upwards.
The ball hits the floor with a speed of 2.40 m/s i.e. u = -2.40 m/s (-ve because the ball hits the ground)
It rebounds with a speed of 1.7 m/s i.e. v = 1.7 m/s (+ve because the ball rebounds in upward direction)
We have to find the change in the ball's momentum. It is given by :
So, the change in the momentum is 1.1275 kg-m/s
Answer:
<em>The work is 750 J</em>
<em>The power is 37.5 watt</em>
Explanation:
<u>Mechanical Work and Power</u>
Mechanical work is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.
Being the force vector and
the displacement vector, the work is calculated as:
If both the force and displacement are parallel, then we can use the equivalent scalar formula:
W=F.s
Power is the amount of energy transferred or converted per unit of time. In the SI, the unit of power is the watt, equal to one joule per second.
The power can be calculated as:
Where W is the work and t is the time.
a)
The table is pushed d=15 m across a room with a force F=50 N, thus the work is:
W=50 * 15 = 750 J
The work is 750 J
b)
The time needed to push the table is t=20 seconds, thus:
The power is 37.5 watt