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Gala2k [10]
3 years ago
13

A baseball thrown by a pitcher is hit by a batter. At the moment when the ball hits the bat, the force exerted on the bat by the

ball
is Fball on bat and the force exerted on the ball by the bat is Fbat on ball The relationship between these forces is

A. Fball on bat = -Fbat on ball
B. Fball on bat = -Fbat on ball

C. Fball on bat < Fbat on ball

D. Fball on bat > Fbat on ball
Physics
1 answer:
Slav-nsk [51]3 years ago
8 0

Newton's Laws of motion describe the motion of an object based on the applied force

The correct option that gives the relationships between the forces is the the option;

\underline{F_{ball}}<u> on bat</u> = \underline{F_{bat}}<u> on ball</u>

<em>(Either option A or B without the minus symbol before </em>F_{bat}<em>, likely typographical error)</em>

<em />

Reason:

Force exerted on the bat by the ball = F_{ball}

Force exerted on the ball by the bat = F_{bat}

Given that the batter hits the ball with the bat, the force exerted by the bat on the ball, F_{bat}, is reacted to by the force of the ball acting on the bat, F_{ball}

According to Newton's third law of motion, action and reaction are equal and opposite. Therefore, at the moment when the ball hits the bat, we have;

\underline{F_{ball}}<u> on bat</u> = \underline{F_{bat}}<u> on ball</u>

<em>Where the force of the bat is high, the ball is accelerated to travel at high speed</em>

Learn more Newton's Laws of motion here:

brainly.com/question/24522313

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A 5-g lead bullet traveling in 20°C air at 300 m/s strikes a flat steel plate and stops.
densk [106]

To solve this problem it is necessary to apply the concepts related to the Kinetic Energy and the Energy Produced by the heat loss. In mathematical terms kinetic energy can be described as:

KE = \frac{1}{2} mv^2

Where,

m = Mass

v = Velocity

Replacing we have that the Total Kinetic Energy is

KE = \frac{1}{2} mv^2

KE = \frac{1}{2} (5*10^{-3})(300)^2

KE =  225J

On the other hand the required Energy to heat up t melting point is

Q_1 = mC_p \Delta T

Q_2 = L_f m

Where,

m = Mass

C_p =Specific Heat

\Delta T =Change at temperature

L_f = Latent heat of fussion

Heat required to heat up to melting point,

Q = Q_1+Q_2

Q = mC_p \Delta T+L_f m

Q = 5*0.128*(327-20) + 5*24.7

Q = 310J

The energy required to melt is larger than the kinetic energy. Therefore the heat of fusion of lead would be 327 ° C: The melting point of lead.

4 0
3 years ago
The horizontal surface on which the block (mass 2.0 kg) slides is frictionless. The speed of the block before it touches the spr
ch4aika [34]

Answer:3.67 m/s

Explanation:

mass of block(m)=2 kg

Velocity of block=6 m/s

spring constant(k)=2 KN/m

Spring compression x=15 cm

Conserving Energy

energy lost by block =Gain in potential energy in spring

\frac{m(v_1^2-v_2^2)}{2}=\frac{kx^2}{2}

2\left [ 6^2-v_2^2\right ]=2\times 10^3\times \left [ 0.15\right ]^2

v_2=3.67 m/s

7 0
3 years ago
Explain how to find the angle between two nonzero vectors. Choose the correct answer below. A. The angle between two nonzero vec
kozerog [31]

Answer:

θ = Cos⁻¹[A.B/|A||B|]

A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result

Explanation:

We can use the formula of the dot product, in order to find the angle between two non-zero vectors. The formula of dot product between two non-zero vectors is written a follows:

A.B = |A||B| Cosθ

where,

A = 1st Non-Zero Vector

B = 2nd Non-Zero Vector

|A| = Magnitude of Vector A

|B| = Magnitude of Vector B

θ = Angle between vector A and B

Therefore,

Cos θ = A.B/|A||B|

<u>θ = Cos⁻¹[A.B/|A||B|]</u>

Hence, the correct answer will be:

<u>A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result</u>

3 0
3 years ago
Can someone please help, ;w;?
SOVA2 [1]
I believe the answer is 3). The cell wall provides protection, it doesn’t control movements of materials in and out of the cell.
7 0
3 years ago
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ASAP HELPPPPPP POP PLEASE​
drek231 [11]

Answer:

The answer is in the attachment

Explanation:

<em>!</em><em>!</em><em>PLEASE</em><em> </em><em>PLEASE</em><em> </em><em>PLEASE</em><em> </em><em>PLEASE</em><em> </em><em>PLEASE</em><em> </em><em>MARK</em><em> </em><em>ME</em><em> </em><em>THE</em><em> </em><em>BRAINLIEST</em><em>!</em><em>!</em>

5 0
2 years ago
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