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Gala2k [10]
2 years ago
13

A baseball thrown by a pitcher is hit by a batter. At the moment when the ball hits the bat, the force exerted on the bat by the

ball
is Fball on bat and the force exerted on the ball by the bat is Fbat on ball The relationship between these forces is

A. Fball on bat = -Fbat on ball
B. Fball on bat = -Fbat on ball

C. Fball on bat < Fbat on ball

D. Fball on bat > Fbat on ball
Physics
1 answer:
Slav-nsk [51]2 years ago
8 0

Newton's Laws of motion describe the motion of an object based on the applied force

The correct option that gives the relationships between the forces is the the option;

\underline{F_{ball}}<u> on bat</u> = \underline{F_{bat}}<u> on ball</u>

<em>(Either option A or B without the minus symbol before </em>F_{bat}<em>, likely typographical error)</em>

<em />

Reason:

Force exerted on the bat by the ball = F_{ball}

Force exerted on the ball by the bat = F_{bat}

Given that the batter hits the ball with the bat, the force exerted by the bat on the ball, F_{bat}, is reacted to by the force of the ball acting on the bat, F_{ball}

According to Newton's third law of motion, action and reaction are equal and opposite. Therefore, at the moment when the ball hits the bat, we have;

\underline{F_{ball}}<u> on bat</u> = \underline{F_{bat}}<u> on ball</u>

<em>Where the force of the bat is high, the ball is accelerated to travel at high speed</em>

Learn more Newton's Laws of motion here:

brainly.com/question/24522313

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A distant galaxy emits light that has a wavelength of 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 n
maksim [4K]

Answer:

A) receding from the earth

B) 3.078x10^6m/s

Explanation:

  • A) receding from the earth

The wavelength went from 434.1nm to 438.6nm, there was an increase in wavelength (also knowecn as redshift due to the doppler efft), this increase is due to the fact that the source that emits the radiation (the distant galaxy) is moving away and therefore the light waves it emits are "stretched", causing us to see a wavelength greater than the original.

  • B) 3.078x10^6m/s

to calculate the relative speed we use the following formula:

v_{rel}=c(1-\frac{\lambda_{1}}{\lambda_{2}} )

where c is the speed of light: c=3x10^8m/s

\lambda_{1} is the wavelength emited by the source, and

\lambda_{2} is the wavelength measured on earth.

we substitute all the values and do the calculations:

v_{rel}=(3x10^8m/s)(1-\frac{434.1nm}{438.6nm} )\\\\v_{rel}=(3x10^8m/s)(1-0.98974)\\\\v_{rel}=(3x10^8m/s)(0.01026)\\\\v_{rel}=3.078x10^6m/s

the relative speed is: 3.078x10^6m/s

5 0
3 years ago
12. An object accelerates 16.3 m/s2 when a force of 4.6 newtons is applied to it.
ladessa [460]
The acceleration of body is given 16.3m/s2 and the force is given 4.6 N then
We know,
Force=mass*acceleration
Then,
Mass=force/acceleration
Mass=4.6/16.3
Mass=0.28kg
5 0
3 years ago
A toroid having a square cross section, 5.00 cm on a side, and an inner radius of 15.0 cm has 500 turns and carries a current of
SCORPION-xisa [38]

Answer:

a).β=0.53x10^{-3} T

a).β=0.40 x10^{-4} T

Explanation:

The magnetic field at distance 'r' from the center of toroid is given by:

\beta =\frac{u_{o}*I*N}{2\pi*r}

a).

N=500\\I=0.800A\\r=15cm*\frac{1m}{100cm}=0.15m\\u_{o}=4\pi x10^{-7}\frac{T*m}{A}  \\\beta=\frac{4\pi x10^{-7}\frac{T*m}{A}*0.8A*500}{2\pi*0.15m} \\\beta=0.53x10^{-3}T

b).

The distance is the radius add the cross section so:

r_{1}=15cm+5cm\\r_{1}=20cm

r_{1} =20cm*\frac{1m}{100cm}=0.20m

\beta =\frac{u_{o}*I*N}{2\pi*r1}

\beta =\frac{4\pi x10^{-7}*0.80A*500 }{2\pi*0.20m} \\\beta=0.4x10^{-3} T

3 0
3 years ago
Which is the appropriate unit of measurement for pitch?
malfutka [58]
Hertz Pitch and frequency
6 0
2 years ago
What is hydraulic pressure?
Ilia_Sergeevich [38]
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3 0
2 years ago
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