Answer:
The required pressure is 6.4866 atm.
Explanation:
The given data : -
In the afternoon.
Initial pressure of tire ( p₁ ) = 7 atm = 7 * 101.325 Kpa = 709.275 Kpa
Initial temperature ( T₁ ) = 27°C = (27 + 273) K = 300 K
In the morning .
Final temperature ( T₂ ) = 5°C = ( 5 + 273 ) K = 278 K
Given that volume remains constant.
To find final pressure ( p₂ ).
Applying the ideal gas equation.
p * v = m * R * T


= 657.2615 Kpa = 6.486 atm
Answer:
YES
Explanation:
Asexual means the plant is identical to the parent
Answer:
The minimum riding speed relative to the whistle (stationary) to be able to hear the sound at 21.0 kHz frequency is 15.7 m/s
Explanation:
The Doppler shift equation is given as follows;

Where:
f' = Required observed frequency = 20.0 kHz
f = Real frequency = 21.0 kHz
v = Sound wave velocity = 330 m/s
= Observer velocity = X m/s
= Source velocity = 0 m/s (Assuming the source is stationary)
Which gives;

330 -
= (20/21)*330
= 330 - (20/21)*330 = 15.7 m/s
The minimum riding speed relative to the whistle (stationary) to be able to hear the sound at 21.0 kHz frequency = 15.7 m/s.
Answer:
Yes
Explanation:
The momentum of an object is given by:

where
m is the mass of the object
v is the velocity of the object
We know that an elephant has a mass much larger than the mass of an ant. However, we see that the momentum of the animal also depends on its velocity.
If the elephant is at rest, its velocity is zero:
v = 0
so its momentum is also zero:
p = 0
And therefore, an ant which is moving (so, non-zero speed) can have more momentum than an elephant, if the elephant is at rest.
The building blocks of nucleic acids, nucleotides are composed of a nitrogenous base, a five-carbon sugar (ribose or deoxyribose), and at least one phosphate group.