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Gemiola [76]
3 years ago
9

You observe a star system for many weeks. The light curve does not show significant changes in brightness, but a series of spect

ra show a spectral feature that cyclically appears as one absorption line, then two, then one again, and so on. Is this a binary system
Physics
1 answer:
mariarad [96]3 years ago
8 0

Based on the changes in the light curve and the behavior of the series of spectra, this is a<u> binary system. </u>

<h3>How is this is binary system?</h3>

The characteristics described are those of a binary system with the specific type of system being the spectroscopic binary system.

This is because in a spectroscopic binary system, there won't be significant changes in brightness but as a result of stars orbiting towards and then away from us, spectral features will appear as alternative absorption lines.

In conclusion, this is a binary system.

Find out more on binary systems at brainly.com/question/15868824.

You might be interested in
(100 pts)<br>Why can't you use distance divide by time to calculate the instantaneous<br>speed?​
Fiesta28 [93]

Answer:

Instantaneous speed means speed at any instant

that means Speed is changing with time

You know speed is distance/time

So that means distance is also changing with time

So we take infinitesimal small distance per infinitesimal small time As we assume speed is constant in infinitesimal small time dt

So, we take speed = ds/dt

ds = infinitesimal small distance

dt = infinitesimal small time

As its ratio is equal to speed at any instant

Note : We are taking infinitesimal small distance

But :) we are taking infinitesimal small time also

As you know if denominator is small fraction is large So fraction always give large value

So it's not O ( this makes confuse to most of students)

So, thanks

Good question

Keep thinking like this :)

4 0
4 years ago
Read 2 more answers
You know your mass is 62 kg but when you stand on a bathroom scale in an elevator it says your mass is 77 kg what is the acceler
lbvjy [14]
In a stationary situation, the weight of person is
W=mg=(62 kg)(9.81 m/s^2) = 608.2 N
This is the weight "felt" by the scale, which is basically the normal reaction applied by the scale on the person, and which uses the value of g (9.81) as reference to convert the weight (602.8 N) into a mass (62 kg).

When the person is in the elevator, the scale says 77 kg. The scale is still using the same value of conversion (9.81), so the apparent weight "felt" by the scale is
W' = m'g=(77 kg)(9.81 m/s^2)=755.4 N
This is the normal reaction applied by the scale on the person, and which is directed upward. Besides this force, there is still the weight W of the person, acting downward. So, if we use Newton's second law:
\sum F = ma
W-W'=ma
where a is the acceleration of the elevator. If we solve for a, we find
a= \frac{W-W'}{m}= \frac{608.2N-755.4N}{62 kg}=-2.37 m/s^2
The negative sign means the acceleration is in the opposite direction of g (which we take positive), so it means the elevator is going upward.
4 0
3 years ago
A person with normal vision can focus on objects as close as a few centimeters from the eye up to objects infinitely far away. T
navik [9.2K]

Concave lenses are thinner in the middle and thicker at the edges.

Answer:

a. When glasses (or contact lenses) are used to correct nearsightedness, the lens should form the image at the far point.

b. If a nearsighted person has a far point df that is 3.50 m from the eye, what is the focal length f1 the contact lenses that the person would need to see an object at infinity clearly?

<em>f </em>1 = -3.50 m

Explanation:

a. Nearsightedness (the person cannot focus on the far point objects) physics of eyesight correction,  can be resolved by using focal length of concave lens as the corrective lens, which correct the eyesight artificially, as the eye’s lens bends the rays from a distant object too much and the rays are brought to a focus before they reach the retina.  A diverging lens bends the ray outwards before they reach the eye’s lens and the rays are brought to a focus on the retina.  

The lens formula to find the focal length of the lens is:

                       1/<em>f</em> = 1u + 1/v

Where, <em>f</em> is the focal length of the lens, u is the object distance, and v  is the image distance.

The light lands in front of the retina, so the image is forming in front of the retina .When concave lens used as a corrective lens the clear vision is achieved, helping to bend the rays of light outwards and the light converge further and reach the retina to form the imagemeaning the lens should form the image at the far point.

b.      The lens formula is,

                        1/<em>f</em> = 1u + 1/v

Here the object distance is infinity,so the reciprocal of infinity gives zero.

    Substitute 0.0  for u   and 0.0 -3.50 m    for   v  

1/<em>f</em> = 1/ -3.50m  + 1/ 0.0

Therefore, the focal length of the contact lenses that the person would need to see an object clearly is -3.50 m

8 0
3 years ago
How many hydrogen atoms are there in 2 molecules of PH3?
atroni [7]
6 because there are 2 molecules and each has 3 hydrogen atoms.
Therefore 2*3=6.
Hope this helps!
7 0
4 years ago
The limit to the eye's acuity is actually related to diffraction by the pupil. What is the angle between two just‑resolvable poi
Alona [7]

Answer: 1.8(10)^{-4} rad

Explanation:

This problem is related to the Rayleigh Criterion, which provides the following formula to find the acuity or limit of resolution of an optic system with circular aperture (the eye in this case):

\theta=1.22\frac{\lambda}{D}

Where:

\theta is the angle of resolution (related to the acuity)

\lambda=554 nm=554(10)^{-9} m is the wavelength of the light

D=3.75 mm=3.75(10)^{-3} m is the diameter of the pupil

Solving:

\theta=1.22 \frac{554(10)^{-9} m}{3.75(10)^{-3} m}

\theta=1.8(10)^{-4} rad

8 0
4 years ago
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