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Levart [38]
3 years ago
7

Please ASAP ……………………….:

Mathematics
1 answer:
wolverine [178]3 years ago
5 0

Answer:

x-3

Step-by-step explanation:

(x  

2

−9)=(x−3)(x+3)

(x  

3

−27)=(x  

3

−3  

3

)=(x−3)(x  

2

−3x+9)

(x  

2

−8x+15)=(x−3)(x−5)

∴ H.C.F. of (x  

2

−9),(x  

3

−27) and (x  

2

−8x+15) is x−3.

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Solve the system using substitution.<br> y - 3x = 1<br> 2y - x = 12<br> ([?], [])
anyanavicka [17]

Answer:

(2, 5)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define Systems</u>

y - 3x = 1

2y - x = 12

<u>Step 2: Rewrite Systems</u>

y - 3x = 1

  1. Add 3x on both sides:                    y = 3x + 1

<u>Step 3: Redefine Systems</u>

y = 3x + 1

2y - x = 12

<u>Step 4: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                    2(3x + 1) - x = 12
  2. Distribute 2:                         6x + 2 - x = 12
  3. Combine like terms:           5x + 2 = 12
  4. Isolate <em>x</em> term:                     5x = 10
  5. Isolate <em>x</em>:                              x = 2

<u>Step 5: Solve for </u><em><u>y</u></em>

  1. Define equation:                    2y - x = 12
  2. Substitute in <em>x</em>:                       2y - 2 = 12
  3. Isolate <em>y </em>term:                        2y = 10
  4. Isolate <em>y</em>:                                 y = 5
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