Answer:
59.55 cm
Explanation:
Note: A meter stick has a length of 100 cm, and it is balanced at 50 cm.
From the principle of moment,
Sum of clockwise moment = sum of anti clockwise moment
Taking moment about the center
mg(50-x) = m'(y-50)g.................. Equation 1
Where m = first mass, m' = second mass, x = position of the first mass, y = position of the second mass, g = acceleration
make y the subject of the equation
y = (m(50-x)/m')+50.................... Equation 2
y = (0.11(50-17)/0.38)+50
y = (0.11(33)/0.38)+50
y = 9.55+50
y = 59.55 cm
Answer:
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Explanation:
Answer:
1.06 secs
Explanation:
Initial speed of sled, u = 8.4 m/s
Final speed of sled, v = 5.8 m/s
Coefficient of kinetic friction, μ = 0.25
Using the impulse momentum theory, we know that the impulse applied to the sled is equal to change in momentum of the sled:
FΔt = mv - mu
where m = mass of the object
Δt = time interval
F = force applied
The force applied on the sled is the frictional force, which is given as:
F = -μmg
where g = acceleration due to gravity
Therefore:
-μmgΔt = mv - mu
-μmgΔt = m(v - u)
-μgΔt = v - u
Making Δt subject of formula:
Δt = (v - u) / -μg
Δt = (5.8 - 8.4) / (-0.25 * 9.8)
Δt = -2.6/ -2.45
Δt = 1.06 secs
It took the sled 1.06 secs to travel from A to B.
Answer:
Explanation:
The length, of the string , fundamental frequency and the tension on the string are related as:
#Since both E and G have the same length and tension on them:
Where are the linear densities, the fundamental frequencies.
#taking square and inverse on both sides, we have:
Hence, the linear density of the G string is 0.00393kg/m
Answer:
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