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Svet_ta [14]
3 years ago
11

A century ago, swords were made from various metals, especially steel. The property that makes steel a good choice for sword mak

ing is _____.
Physics
2 answers:
8_murik_8 [283]3 years ago
8 0
Hardness and strength
andreev551 [17]3 years ago
3 0

<em>The answer to this question is strength</em>


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A 20-lb force acts to the west while an 80-lb force acts 45° east of north. The magnitu 80 lb 70 lb 067 lb 100 lb
natulia [17]

Answer:

option C

Explanation:

given,

force act on west  = 20 lb

force act at 45° east of north = 80 lb

magnitude of force = ?

∑ F y  =  80 cos 45⁰

    F y =  56.57 lb

magnitude of forces in x- direction

∑ F x = -20 + 80 sin 45⁰

        = 36.57 lb

net force

F = \sqrt{F_x^2+F_y^2}

F = \sqrt{56.57^2+36.57^2}

F = 67.36 lb≅ 67 lb

hence, the correct answer is option C

4 0
3 years ago
How many Newtons of force does it take to move a 53 kilogram object?
Sidana [21]
519.75N

explanation: good luck on whatever assignment
3 0
3 years ago
What evidence supports the conclusion that a chemical reaction has occurred?
GalinKa [24]

Answer:

Precipitation formed

Temperature change

fizzing and hissing

bubbles

change in state

Explanation:

3 0
2 years ago
What happens when stress builds up at faults?
Harlamova29_29 [7]

Answer:

The answer is D because when the faults move that is the tectonic plates moving. So earth quakes will be forming when the fault moves.

Explanation:

3 0
3 years ago
Read 2 more answers
What is the magnitude of the momentum change of two gallons of water (inertia about 7.3 kg ) as it comes to a stop in a bathtub
aliya0001 [1]

We know that the change in momentum is equals to the product of force and time that is impulse (  F \times t). Therefore, we need to determine the value of that the water is in air by using the second equation of motion,

s=ut+\frac{1}{2} gt^2

Here, u is initial velocity which is zero.

s= \frac{1}{2} gt^2 \\\\ t = \sqrt{\frac{2s}{g} }.

Thus, impulse

= F \times \sqrt{\frac{2s}{g} }

From Newton`s second law,

F =mg

Therefore, impulse

= mg \times \sqrt{\frac{2s}{g} } = m \sqrt{2gs}

Given,  m = 7.3 kg and s = 2.0 m

Substituting these values, we get

Change in momentum = impulse  

= 7.3 \ kg \sqrt{2 \times 9.8 \ m/s^2 \times 2.0 \ m } = 45 .7 \ Ns.

8 0
3 years ago
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