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4 years ago

A statement made prior to an experiment, and based on little scientific evidence, is

1 answer:

7 0

A- hypothesis
You usually write hypothesis in science it’s something that can usually be tested.

B- prediction
Made before you do an science experiment, they’re usually like what you think could happen or will happen.

C- theory
Theses aren’t used with scientific evidence, they’re usually things that people believe happened. Example: Some believe Big Foot is real. But no one will ever know because its a theory

D- is already been eliminated, not all are right.

Answer is A

Hope this helped :)

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Right hand rule exercise

saveliy_v [14]

Answer:

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3 years ago

A compact car, mass 664 kg, is moving at 19 km/h toward the east. What is the car's momentum in kg x m/s?

Natasha2012 [34]

Answer:

3504.4 kgm/s

Explanation:

First, convert km/hr to m/s:

19 km/hr x 1000m/1km x 1/60min x 1/60s = 5.28 m/s

p = mv

p = (664 kg)(5.28 m/s) = 3504.4 kgm/s

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3 years ago

Use F = 1/T as your basis:

DaniilM [7]

Frequency=60Hz

$\\ \rm\rightarrowtail \nu=\dfrac{1}{T}$

$\\ \rm\rightarrowtail T=\dfrac{1}{\nu}$

$\\ \rm\rightarrowtail T=\dfrac{1}{60}$

$\\ \rm\rightarrowtail T=1.67\times 10^{-4}s$

$\\ \rm\rightarrowtail T=16.7\times 10^{-3}s$

$\\ \rm\rightarrowtail T=16.7ms$

5 0

2 years ago

A 20~\mu F20 μF capacitor has previously charged up to contain a total charge of Q = 100~\mu CQ=100 μC on it. The capacitor is t

sertanlavr [38]

Explanation:

The given data is as follows.

C = $20 \times 10^{-6} F$

R = $100 \times 10^{3}$ ohm

$Q_{o} = 100 \times 10^{-6}$ C

Q = $13.5 \times 10^{-6} C$

Formula to calculate the time is as follows.

$Q_{t} = Q_{o} [e^{\frac{-t}{\tau}]$

$13.5 \times 10^{-6} = 100 \times 10^{-6} [e^{\frac{-t}{2}}]$

0.135 = $e^{\frac{-t}{2}}$

$e^{\frac{t}{2}} = \frac{1}{0.135}$

= 7.407

$\frac{t}{2} = ln (7.407)$

t = 4.00 s

Therefore, we can conclude that time after the resistor is connected will the capacitor is 4.0 sec.

4 0

3 years ago

Four +2 μC charges are placed at the positions (10 cm, 0 cm), (−10 cm, 0 cm), (0 cm, 10 cm), and (0 cm, −10 cm) such that they f

Rufina [12.5K]

Answer:

The force on the charge at the origin is 0 N .

Explanation:

All charges are positive. So, in x axis force exerted by the charge located in the position (10 cm, 0 cm) will be canceled with the force exerted by the charge located in the position (-10 cm, 0 cm). In the same way, in y axis the force exerted by the charge located in the position (0 cm, 10 cm) will be canceled with the force exerted by the charge located in the position (0 cm, -10 cm).

4 0

4 years ago