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Vlada [557]
3 years ago
15

Give any two reasons that hydrogen is kept in group 1 in Modern Periodic Table​

Chemistry
1 answer:
xeze [42]3 years ago
3 0

Answer:

Hydrogen is usually classified as a group 1 element since it has one valence electron, just like group 1 metals.

Explanation:

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IrinaK [193]

Answer:

I dont have a answer

Explanation:

4 0
3 years ago
Read 2 more answers
If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio
bulgar [2K]

Answer:

m_{Cd(OH)_2}=36.6 gCd(OH)_2

Explanation:

Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2}  =0.75molCd(OH)_2

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2

Best regards.

4 0
3 years ago
A scientific theory is
vlada-n [284]
The answer is A. an explanation
7 0
3 years ago
Please help will mark you brainiest! Use word bank when answering the question!
zheka24 [161]

Answer:

Blank 1: varying

Blank 2: constant

Explanation:

7 0
3 years ago
What is the term for a type of reaction in which an acid and a base react to produce a salt and water?
WINSTONCH [101]
Neutralization 
is the probable answer, which I don't know how to explain, but I know that's the answer because I learned about it a few years ago and I'm pretty smart. =]

5 0
3 years ago
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