Answer:
1Ag+2S⇔1Ag2S
Explanation:
The first step is to see how many of each element are on each side of the equation. There is one silver on the left and one silver on the right, so you can leave those alone. However, there is one sulfur on the left and two on the right. You cannot multiply the right by 2 because then that would upset the balance of the silver, but you can multiply the sulfur by 2. Therefore, the equation should be 1Ag+2S⇔1Ag2S. Hope this helps!
(a) The mass of hydrogen sulfide produced in the reaction is 9.44 g.
(b) Water is the limiting reagent in the given reaction.
<h3>
Mass of hydrogen sulfide produced</h3>
Al2S3 + 6H2O ---> 2Al(OH)3 + 3H2S
mass of water in the reaction = 6(18 g/mol) = 108 g/mol
mass of hydrogen sulfide in the reaction: = 3(34) = 102 g/mol
108 g/mol of H2O ------- > 102 g/mol of H2S
10 of H2O -----------> ?
= 9.44 g
Aluminum sulfide will be completely consumed by the reaction while some fraction of water will remain. Thus, water is the limiting reagent in the given reaction.
Learn more about limiting reagents here: brainly.com/question/26905271
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Answer:
C. Decreasing the temperature of the system.
Explanation:
Decreasing the temperature of the system increases the chance of a reaction when two molecules collide.
Skeletal Equation
Ba(NO3)2 + KCl = BaCl2+ KNO3
Balanced equation
Ba(NO3)2 + 2KCl = BaCl2 + 2KNO3