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andrey2020 [161]
3 years ago
11

What are some of the forms of energy you used today? How did you use them?

Chemistry
1 answer:
klio [65]3 years ago
8 0

Answer:

Heat or Thermal energy, Solar Energy, Chemical energy, electrical energy, mechanical energy

Explanation:

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The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In t
Sloan [31]

Answer:

Mass =  42.8g

Explanation:

4 NH 3 ( g ) + 5 O 2 ( g ) ⟶ 4 NO ( g ) + 6 H 2 O ( g )

Observe that every 4 mole of ammonia requires 5 moles of oxygen to obtain 4 moles of Nitrogen oxide and 6 moles of water.

Step 1: Determine the balanced chemical equation for the chemical reaction.

The balanced chemical equation is already given.

Step 2: Convert all given information into moles (through the use of molar mass as a conversion factor).

Ammonia = 63.4g × 1mol / 17.031 g = 3.7226mol

Oxygen = 63.4g × 1mol / 32g = 1.9813mol

Step 3: Calculate the mole ratio from the given information. Compare the calculated ratio to the actual ratio.

If all of the 1.9831 moles of oxygen were to be used up, there would need to be 1.9831 × 4 / 5 or 1.5865 moles of Ammonia. We have 3.72226 moles of ammonia - Far excess. Because there is an excess of Ammonia, the Oxygen amount is used to calculate the amount of the products in the reaction.

Step 4: Use the amount of limiting reactant to calculate the amount of H2O produced.

5 moles of O2  = 6 moles of H2O

1.9831 moles = x

x = (1.9831 * 6 ) / 5

x = 2.37972 moles

Mass of H2O = Molar mass * Molar mass

Mass = 2.7972 * 18

Mass =  42.8g

6 0
3 years ago
Please help with any
lys-0071 [83]
10 down: Particle with no charge

Answer: Neutron
3 0
3 years ago
HELP!! SYNTHESIS QUIZ!!
Juliette [100K]
Ok it’s 38 so I hope that helps ok
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3 years ago
What is 155.4g÷8.70mL, rounded to the correct number of significant figures
OLEGan [10]

Answer:

17.9g/ml

Explanation:

5 0
3 years ago
A certain shade of blue has a frequency of 7.07 × 1014 Hz. What is the energy of exactly one photon of this light?
IRISSAK [1]
E = HF, where H is Planck's constant, 6.63 x 10 -  34 j.s
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3 years ago
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