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pshichka [43]
2 years ago
7

What is your wheel and axle

Physics
2 answers:
Crank2 years ago
8 0

Answer:

Pls mark me brainliest

Explanation:

The wheel and axle is a simple machine consisting of a wheel attached to a smaller axle so that these two parts rotate together in which a force is transferred from one to the other.

Fittoniya [83]2 years ago
7 0

Explanation:

<em>The</em><em> </em><em>wheel</em><em> </em><em>and</em><em> </em><em>axle</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>type</em><em> </em><em>of</em><em> </em><em>simple</em><em> </em><em>machine</em><em> </em><em>used</em><em> </em><em>to</em><em> </em><em>make</em><em> </em><em>tasks</em><em> </em><em>easier</em><em> </em><em>in</em><em> </em><em>terms</em><em> </em><em>of</em><em> </em><em>manipulating</em><em> </em><em>force</em><em> </em><em>by</em><em> </em><em>applying</em><em> </em><em>the</em><em> </em><em>concept</em><em> </em><em>of</em><em> </em><em>mechanical</em><em> </em><em>advantage</em><em>. </em><em> </em>

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vredina [299]
The answer is B (The second one). I'm not sure though.
3 0
3 years ago
What is the Electromagnetic Spectrum? in your own words
Inessa05 [86]
The electromagnetic spectrum is the system of frequencies that show electromagnetic radiation, respective wavelengths, and photon energies. Some examples of frequencies found on the electromagnetic spectrum are radio waves, microwaves, infrared, optical, ultraviolet, X-rays, and gamma-rays.
5 0
2 years ago
A balloon filled with helium gas at 20°C occupies 4.91 L at 1.00 atm. The balloon is immersed in liquid nitrogen at -196°C, whil
mrs_skeptik [129]

Answer:

0.25 L

Explanation:

P_1 = Initial pressure = 1 atm

T_1 = Initial Temperature = 20 °C

V_1 = Initial volume = 4.91 L

P_2 = Final pressure = 5.2 atm

T_2 = Final Temperature = -196 °C

V_2= Final volume

From ideal gas law we have

\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow V_2=\dfrac{P_1V_1T_2}{T_1P_2}\\\Rightarrow P_2=\dfrac{1\times 4.91(273.15-196)}{(20+273.15)\times 5.2}\\\Rightarrow V_2=0.24849\ L\approx 0.25\ L

The pressure experienced by the balloon is 0.25 L

7 0
3 years ago
A 2 eV electron encounters a barrier 5.0 eV high and width a. What is the probability b) 0.5 that it will tunnel through the bar
denis23 [38]

Answer:

The tunnel probability for 0.5 nm and 1.00 nm are  5.45\times10^{-4} and 7.74\times10^{-8} respectively.

Explanation:

Given that,

Energy E = 2 eV

Barrier V₀= 5.0 eV

Width = 1.00 nm

We need to calculate the value of \beta

Using formula of \beta

\beta=\sqrt{\dfrac{2m}{\dfrac{h}{2\pi}}(v_{0}-E)}

Put the value into the formula

\beta = \sqrt{\dfrac{2\times9.1\times10^{-31}}{(1.055\times10^{-34})^2}(5.0-2)\times1.6\times10^{-19}}

\beta=8.86\times10^{9}

(a). We need to calculate the tunnel probability for width 0.5 nm

Using formula of tunnel barrier

T=\dfrac{16E(V_{0}-E)}{V_{0}^2}e^{-2\beta a}

Put the value into the formula

T=\dfrac{16\times 2(5.0-2.0)}{5.0^2}e^{-2\times8.86\times10^{9}\times0.5\times10^{-9}}

T=5.45\times10^{-4}

(b). We need to calculate the tunnel probability for width 1.00 nm

T=\dfrac{16\times 2(5.0-2.0)}{5.0^2}e^{-2\times8.86\times10^{9}\times1.00\times10^{-9}}

T=7.74\times10^{-8}

Hence, The tunnel probability for 0.5 nm and 1.00 nm are  5.45\times10^{-4} and 7.74\times10^{-8} respectively.

6 0
3 years ago
A basketball player makes a jump shot. The 0.630-kg ball is released at a height of 1.80 m above the floor with a speed of 7.09
N76 [4]

mass of the ball m = 0.63 kg

initial height h = 1.8 m

final height h ' = 3.03 m

initial speed v = 7.09 m / s

final speed v ' = 4.21 m / s

Let the work done on the ball by air resistance W = ?

we know from law of conservation of energy ,

total energy at height h + work done by air = total energy at height h '

  mgh + ( 1/ 2) mv^ 2 + W = mgh ' + ( 1/ 2) mv'^ 2

0.630*9.8*1.8 + 0.63*7.09^2 + W = mgh ' + ( 1/ 2) mv'^ 2

From there you can find W

if there is negative sign indicates it work opposite direction to motion

6 0
2 years ago
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