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pshichka [43]
2 years ago
7

What is your wheel and axle

Physics
2 answers:
Crank2 years ago
8 0

Answer:

Pls mark me brainliest

Explanation:

The wheel and axle is a simple machine consisting of a wheel attached to a smaller axle so that these two parts rotate together in which a force is transferred from one to the other.

Fittoniya [83]2 years ago
7 0

Explanation:

<em>The</em><em> </em><em>wheel</em><em> </em><em>and</em><em> </em><em>axle</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>type</em><em> </em><em>of</em><em> </em><em>simple</em><em> </em><em>machine</em><em> </em><em>used</em><em> </em><em>to</em><em> </em><em>make</em><em> </em><em>tasks</em><em> </em><em>easier</em><em> </em><em>in</em><em> </em><em>terms</em><em> </em><em>of</em><em> </em><em>manipulating</em><em> </em><em>force</em><em> </em><em>by</em><em> </em><em>applying</em><em> </em><em>the</em><em> </em><em>concept</em><em> </em><em>of</em><em> </em><em>mechanical</em><em> </em><em>advantage</em><em>. </em><em> </em>

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A 0.683 kg mass moves in SHM at the end of a spring. It takes 1.41 s to move from the position with the spring fully extended to
dsp73

Answer:

Spring constant of the spring will be equal to 9.255 N /m          

Explanation:

We have given mass m = 0.683 kg

Time taken to complete one oscillation is given T = 1.41 sec

We have to find the spring constant of the spring

From spring mass system time period is equal to T=2\pi \sqrt{\frac{m}{K}}, here m is mass and K is spring constant

So 1.41=2\times 3.14\sqrt{\frac{0.683}{K}}

0.2245=\sqrt{\frac{0.683}{K}}

Squaring both side

0.0504=\frac{0.4664}{K}

K=9.255N/m

So spring constant of the spring will be equal to 9.255 N /m

7 0
3 years ago
The department of insurance and safety is led by what official
lawyer [7]

Answer: Georgia Department of Insurance

Explanation: I hope this help :]

6 0
3 years ago
A van is traveling with an initial velocity of 12 m/s. The driver takes a time of 45 seconds to speed up to a velocity of 20 m/s
Rufina [12.5K]
  • Initial velocity=u=12m/s
  • Final velocity=v=20m/s
  • Time=t=45s

\\ \rm\hookrightarrow Acceleration=\dfrac{v-u}{t}

\\ \rm\hookrightarrow Acceleration=\dfrac{20-12}{45}

\\ \rm\hookrightarrow Acceleration=\dfrac{8}{45}

\\ \rm\hookrightarrow Acceleration=0.1m/s^2

Now

  • Distance=s

\\ \rm\hookrightarrow v^2-u^2=2as

\\ \rm\hookrightarrow (20)^2-12^2=2(0.1)s

\\ \rm\hookrightarrow 400-144=0.2s

\\ \rm\hookrightarrow 256=0.2s

\\ \rm\hookrightarrow s=\dfrac{256}{0.2}

\\ \rm\hookrightarrow s=1280m

4 0
3 years ago
A 1-kilogram turtle crawls in a straight line at a speed of 0.01 m/sec what is the turtles momentum
Arada [10]

Momentum = (mass) x (speed) = (1 kg) x (0.01 m/s)  =  0.01 kg-m/s

4 0
3 years ago
at certain times the demand for electric energy is low and electric energy is used to pump water to a reservoir 45 m above the g
Readme [11.4K]

The mass of water that must be raised is 5.25\cdot 10^7 kg

Explanation:

Since the process is 70% efficiency, the power in output to the turbine can be written as

P_{out} = 0.70 P_{in}

where P_{in} is the power in input.

The power in input can be written as

P_{in} = \frac{W}{t}

where

W is the work done in lifting the water

t = 3 h = 10,800 s is the time elapsed

The work done in lifting the water is given by

W=mgh

where

m is the mass of water

g=9.8 m/s^2 is the acceleration of gravity

h = 45 m is the height at which the water is lifted

Combining the three equations together, we get:

P_{out} = 0.70 \frac{mgh}{t}

Where

P_{out} = 150 MW = 150\cdot 10^6 W

And solving for m, we find:

m=\frac{Pt}{0.70gh}=\frac{(1.50\cdot 10^6)(10800)}{(0.70)(9.8)(45)}=5.25\cdot 10^7 kg

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

3 0
3 years ago
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