Two vectors have magnitudes of 10 and 15. The angle between them when they are drawn with their tails at the same point is 65. The component of the longer vector along the line of the shorter is 6.33 .
A vector is a quantity or phenomenon that has two independent properties: magnitude and direction. The term also denotes the mathematical or geometrical representation of such a quantity. Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.
The taller component will be 15 . There will be two components taller component , one in the direction of shorter component and other perpendicular to the shorter wavelength .
The component of longer wavelength in the direction of shorter will be
= 15 cos (theta ) = 15 cos (65) = 6.33
where theta is the angle between both the vectors
To learn more about vectors here
brainly.com/question/13322477
#SPJ4
Answer:
A. A car can still be moving without acceleration when it has some velocity.
B. A car can come to a stop when moving itself when it has some de acceleration.
C.A ca can start at 0 m/s and speed up to 15 m/s when it has some acceleration.
Explanation:
A. since the car has no acceleration the velocity of the car would help it moving.
B. when the car is moving with some velocity but coming to a stop this is possible of and only if it has some de acceleration
C. since the speed of the car increases from 0 to 15 m/s acceleration is involved. If the speed was constant there would be no acceleration involved.
Answer:
A net torque applied to an object causes the angular velocity of the object to change.
Explanation:
The rotational equivalence of force is called a Torque. Thus, a net torque will make an object to rotate with an angular acceleration. Due tothe fact that all rotational motions have an axis of rotation, then a torque must be defined about a rotational axis. A force applied to a point on an object about the axis of rotation is known as a torque.
<span>They are still structured as monopolies that bundle together disparate energy </span>
The proper time would be the time measured in the rest frame of the event, so in this case the observer on mars would measure the proper time.