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loris [4]
3 years ago
14

Which of the following objects have kinetic energy? check all that apply

Chemistry
1 answer:
Aleks [24]3 years ago
4 0

Answer:

what are the options?

Explanation:

do you have multiple choice for this question?

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Identify the terms described by selecting the correct word from the drop-down menu.
Ksju [112]

Answer: Matter

Biosphere

Explanation:

7 0
2 years ago
What volume of 0.140 HCl is needed to neutralize 2.58 of Mg(OH)2<br> ? ...?
elena-s [515]
To make a first step you have to know the balanced form for neutralization formula: Mg(OH)2(aq)+2HCl(aq)--\ \textgreater \ 2H2O+Mg(aq)+Cl(aq)&#10;
According to this, you can <span>calculate what you are being asked :</span>0.0442molMg(OH)2(x)(2molHCl)/(1molMg(OH)2)=0.0885molHCl
Then we have : 0.140MHCl=0.140(mol/L)HCl
Hope everything is clear, here is the exact answer you need : V=(0.0885molHCl)/(0.140(mol/L)HCl)=0.632LHCl&#10;

8 0
3 years ago
How many hydrogen atoms are in an acyclic alkane with 8 carbon atoms?
vfiekz [6]
The general formula of acyclic alkane is CnH2n+2. 

<span>When n = 8 : </span>
<span>Number of hydrogen atoms = 2n + 2 = 18</span>
7 0
3 years ago
In a laboratory experiment the reaction of 3.0 mol of H2 with 2.0 mol of I2 produced 1.0 mole of HI. Determine theoratical yield
Kobotan [32]

Answer:

Theoretical yield of HI is 512 g.

The percent yield for this reaction is 25%.

Explanation:

H_2+I_2\rightarrow 2HI

Moles of hydrogen gas = 3.0 moles

Moles of iodine gas  = 2.0 moles

According to reaction 1 mol of hydrogen gas reacts with 1 mol of iodine gas.

Then 3.0 moles of hydrogen gas reacts with 3.0 mol of iodine gas. But there are 2.0 moles of iodine gas. Hence,Iodine is a limiting reagent. The production of HI will depend upon iodine gas moles.

According to reaction , 1 mol of iodine gas gives 2 moles of HI.

Then 2 moles of iodine gas will give:

\frac{2}{1}\times 2 mol=2 mol of HI

Theoretically we will get 4 moles of HI.

Theoretical yield of HI =  4 mol × 128 g/mol= 512 g

Experimental yield of HI = 1.0 mol

= 1 mol × 128 g/mol= 128 g

\%yield=\frac{\text{Experimental yield}}{\text{Theoretical yield}} \times 100

\%yield=\frac{128 g}{512 g}\times 100=25\%

The percent yield for this reaction is 25%.

6 0
3 years ago
If an objects mechanical energy is equal to its potential energy how much Kinetic energy does it have explain
Phantasy [73]
None because it is not moving if the mechanical and potential are equals.
8 0
3 years ago
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