Answer:
y = 1/3x - 2
Step-by-step explanation:
We are asked to find the equation of a line with two points
Step1: find the slope
m = (y_2 - y_1)/(x_2 - x_1)
( 0 , -2) (6 , 0)
x_1 = 0
y_1 = -2
x_2 = 6
y_2 = 0
Insert the values
m = ( 0 - (-2)/ (6 - 0)
m = ( 0 + 2)/(6 - 0)
m = 2/6
m = (2/2)/(6/2)
m = 1/3
Step 2 : substitute m into the equation of line
y = mx + c
y = intercept y
m = slope
x = intercept x
c = intercept
y = 1/3x + c
Step 3: sub any of the two points
Let's pick ( 6 ,0)
x = 6
y = 0
Insert the values into
y = 1/3x + c
0 = 1/3(6) + c
0 = 1*6/3 + c
0 = 6/3 + c
0 = 2 + c
c = 0 - 2
c = -2
Sub c = -2
y = 1/3x - 2
The equation of the line is
y = 1/3x - 2
f(x) is a quadratic equation with the x-side squared and a is positive which means that the graph of the function is a parabola facing up. The range of f(x) is given by {y|y ≥ k}, where k is the y-coordinate of the vertex.
, written in vertex form is
, where (h, k) = (-1, -11)
Therefore, range ={y|y ≥ -11}
Sorry people send you links instead of actually helping you
ANSWER—C.................................
The (3, 1/5) would be a solution while the (-1,1) wouldn’t because when you write this equation in the slope intercept form which is y = 3/5x - 8/5
1/5 = 3/5 (3) - 8/5
would end up with 1/5 = 1/5 which is write
While,
1 = 3/5 (-1) - 8/5
Would end up with
1 = 11/5 which is wrong
