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3 years ago

Help please, would be much appreciated

Mathematics

1 answer:

andrew-mc [135]3 years ago

5 0

Hey there! I'm happy to help!

We see that all of our y-values go negative and our x-values stay the same. It isn't a rotation because then our x-values will switch, but they haven't switched in our problem, so A and D are incorrect.

Reflecting over the line y=x is just reflecting over a diagonal line, and that will switch the x-value as well.

The correct answer is B. reflect over the x-axis. All of the x-values stay the same here, but the y-values are all on the other side of the x-axis, so they are all negative now, and this matches the change we see with our points.

Have a wonderful day and keep on learning! :D

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Answer:

48°

Step-by-step explanation:

we know that opposite angle of parallelogram is equal

so,

angel C is equal to opposite angle H

H = 48

angle C = 48°

angle R = 132°

angle H = 48° (opposite of angle C)

angle S = 132°(opposite of angle R)

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A jeweler had a fixed amount of gold to make bracelets and necklaces. The amount of gold in each bracelet is 5 grams and the amo

krok68 [10]

Answer:

The jeweler made 9 necklaces.

The jeweler made 8 bracelets.

Step-by-step explanation:

x = number of bracelets

y = number of necklaces

17 = x + y

238 = 5x + 22y

Make one of the coefficients, x, the same.

17 = x + y

Multiply this equation by 5.

85 = 5x + 5y

Subtract the equations to get rid of x.

(238 = 5x + 22y) - (85 = 5x + 5y)

(5x - 5x) + (22y - 5y) = 238 - 85

22y - 5y = 238 - 85

17y = 153

y = 153/17 = 9

The jeweler made 9 necklaces. Substitute this back into one of the equations to find x.

17 = x + y

17 = x + 9

17 - 9 = x

x = 8

238 = 5x + 22y

238 = 5x + 22(9)

238 = 5x + 198

238 - 198 = 5x

40 = 5x

x = 40/5

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8 0

3 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

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3 years ago