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3 years ago

Brainiest to whoever right

Mathematics

2 answers:

sasho [114]3 years ago

6 0

Is there more context to the question?

anzhelika [568]3 years ago

5 0

Answer:

∠1 = 64°

∠2 = 116°

Step-by-step explanation:

Let x = supplement and x + 52 = the one angle. Set up this equation:

(x) + (x + 52) = 180

2x + 52 = 180

Subtract 52 from both sides.

2x = 128

Divide both sides by 2, and you get x = 64.

Keep in mind this equals the supplement. To find the measure of the other angle, add 52 and you get 116

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Tcecarenko [31]

Answer:Sorry i have no time to read it all bro

Step-by-step explanation:

4 0

3 years ago

If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 4x^{-2}$
[u] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

2 years ago

PLS DO THIS :(( I WILL GIVE U BRAINLEST its a pdf!!

Sliva [168]

I cant see the picture :(

7 0

2 years ago

Need help with this problem, it's got me stuck PLZ

faust18 [17]

24x^2 +25x - 47 53

----------------------- = -8x -3 - ---------------

ax-2 ax-2

add 53/ax-2 to each side

24x^2 +25x - 47+53

----------------------- = -8x -3

ax-2

24x^2 +25x +6

----------------------- = -8x -3

ax-2

multiply each side by ax-2

24x^2 +25x +6 = (ax-2) (-8x-3)

multiply out the right hand side

24x^2 +25x +6 = -8ax^2 +16x-3ax +6

24 = -8a 25 = 16 -3a

a = -3 9 = -3a

a = -3

Choice B

6 0

3 years ago

15. 3x – 4y = -1 5x + 2y = 7

never [62]

Answer:

x = 1, y = 1

Step-by-step explanation:

3x - 4y = -1

5x + 2y = 7

If we multiply the whole second equation by 2, we get:

10x + 4y = 14

Adding this to the first equation:

10x + 4y + 3x - 4y = 14 - 1

13x = 13

x = 1

Applying this to the second equation:

5 (1) + 2y = 7

2y = 2

y = 1

8 0

3 years ago