You would call that the Meniscus.
I believe it is Sodium. I could be wrong though.
Answer: option C) 5x10−6 M
Explanation:
Recall that pH + pOH = 14
9.0 + pOH = 14
pOH = 14 - 9.0
pOH = 5.0
Then, find the concentration of aqueous Ba(OH)2 that yields a pOH of 5.0
Ba(OH)2 = Ba2+ + 2OH-
Since pOH = - log(OH-)
5.0 = - 2 x log(OH-)
2 x (OH-) = Antilog (-5.0)
2 x (OH-) = 0.00001
(OH-) = 0.00001/2
(OH-) = 0.000005
Then, 0.000005 in standard form = 5x10−6 M
Answer:
A- Solubility decrease.
B- Solubility increase.
C- No solubility change.
Explanation:
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In this case, since the solubility of salt stands for the maximum amount of salt that can be added to a specific mass of water, usually 100 g; we need to take into account that for table salt in aqueous solution, the higher the temperature the larger the solubility and the lower the temperature the smaller the solubility; it means that more salt is dissolved in the same mass of water at higher temperatures and vice versa. Therefore, A- would decrease the solubility as the solution is cooled down and B- would increase the solubility as the solution is heated up.
Moreover, since the mass of water is assumed to remain the same, adding more salt do not affect the solubility but increase the degree of saturation of the solution up to supersaturated, yet the solubility remains unchanged.
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Answer:
a) 0.2118 mol of I₂ is produced.
b) 49.93 g of I₂ is produced.
Explanation:
a) The balanced equation shows that to produce 1 mol of I₂ we need 2 mol of CuCl₂ . Therefore, the amount of I₂ produced will always be half the amount of CuCl₂ given.
b) In order to calculate the mass of I₂ produced we need to know its molar mass:
Each mole of I₂ weighs 253.8 g, therefore MM = 253.8 g/mol.