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3 years ago

L.c.m of 84 ,27,35,45 please help

Mathematics

1 answer:

den301095 [7]3 years ago

8 0

Answer:

3780

Step-by-step explanation:

84 = 2^2 * 3 * 7

27 = 3^3

35 = 5 * 7

45 = 3^2 * 5

lcm = 2^2 * 3^3 * 5 * 7 = 3780

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A snail going full speed was taking 1/5 of a minute to move

cluponka [151]

Answer:

84 seconds or 1 min and 24 seconds

Step-by-step explanati

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3 years ago

The volume of a cylinder is the 48 ft the area of the base is 12 ft. what is the height of the cylinder

monitta

4 ft is the height of the cylinder

MESSAGE ME OR COMMENT IF YOU WOULD LIKE A MORE IN DEPTH EXPLANATION

8 0

4 years ago

Sam and Lou need a total of 1 foot of wire for a science project. Sam's wire measured 7/8- foot long. Do they have enough wire f

Reil [10]

Answer:

Yes, Sam and Lou have enough wire for science project.

Step-by-step explanation:

There is some data missing in the question, so complete question is below:

$Sam\ and\ Lou\ need\ a\ total\ of\ 1\ foot\ of\ wire\ for\ science\ project.$ $Sam's\ wire\ measured\ 8/12\ foot\ long.\ Lou's\ measured\ 7/8-\ foot \ \ long.$ $Do\ they\ have\ enough\ wire\ for\ the\ science\ project?$ $Explain \ your\ reasoning.$

Now, to get that whether they have enough wire for the science project or not.

Measurement of Sam's wire = $\frac{8}{12} \ foot.$

Measurement of Lou's wire = $\frac{7}{8}\ foot.$

Now, adding both the wires of Sam and Lou:

$\frac{8}{12} +\frac{7}{8} \\\\=\frac{16+21}{24} \\\\=\frac{37}{24}$

$=1\frac{13}{24} \ feet.$

As, Sam and Lou need a total of 1 foot of wire for the science project.

And, we see that the Sam's wire and Lou's wire combining gets $1\frac{13}{24}\ feet$ which is more than 1 foot.

Thus, wire they have is enough for science project.

Therefore, yes, Sam and Lou have enough wire for science project.

5 0

3 years ago

A cone has a volume of about 235.5 cubic centimeters. If the height is 9 centimeters what is the radius of the cone?

sp2606 [1]

Volume of a cone = 1/3 π r² h

235.5 = 1/3 (3.14) r² (9)

(3.14) r² (9) = 706.5

r² = 25

r = 5

Answer: Radius = 5 cm

8 0

3 years ago

Read 2 more answers

X^3+7x^2+13x+4=0 Show all work

Softa [21]

$\displaystyle\\
x^3+7x^2+13x+4=0\\\\
x^3+\underbrace{4x^2+3x^2}_{7x^2}+\underbrace{12x+x}_{13x}+4=0\\\\
(x^3+4x^2) + (3x^2 + 12x)+(x+4)=0\\\\
x^2(x+4)+3x(x+4)+(x+4)=0\\\\
(x+4)(x^2 + 3x +1)=0\\\\
x+4 = 0~~~\Longrightarrow~~~\boxed{x_1 = -4}\\\\
x^2 + 3x +1=0\\\\
x_{23}= \frac{-b\pm \sqrt{b^2-4ac} }{2a}= \frac{-3\pm \sqrt{3^2-4\cdot 1 \cdot 1} }{2\cdot 1}= \frac{-3\pm \sqrt{5} }{2}\\\\
\boxed{x_2 = \frac{-3-\sqrt{5} }{2}}\\\\
\boxed{x_3 = \frac{-3+\sqrt{5} }{2}}$

4 0

4 years ago

L.c.m of 84 ,27,35,45 please help​

L.c.m of 84 ,27,35,45 please help