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Ugo [173]
3 years ago
7

L.c.m of 84 ,27,35,45 please help​

Mathematics
1 answer:
den301095 [7]3 years ago
8 0

Answer:

3780

Step-by-step explanation:

84 = 2^2 * 3 * 7

27 = 3^3

35 = 5 * 7

45 = 3^2 * 5

lcm = 2^2 * 3^3 * 5 * 7 = 3780

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Wayne is going to paint the side of the house shown in the diagram. What is the area that will be painted? Please explain how u
goblinko [34]
First find the area of the rectangle  by multiplying the length and width of the rectangle, so 12 x25=300. Then find the area of the triangle, which is length x height/ 2. So 8 x 25=200/2=100. Then add the two answers together to get 400.
3 0
2 years ago
Hey i need help with system of equations.<br> i uploaded a doxs file you can onpen it in google docs
Art [367]

Answer:

<h2>PART A: x = 15 and y = -8</h2><h2>PART B: x = -5 and y = 3</h2>

Step-by-step explanation:

PART A:

The first equation is x + y = 7\\y = 7 - x  .............(a)

The second equation is 3x - 2y = 1\\2y = 3x - 1

Putting the value of y from (a) in the above equation, we get 2y = 3x - 1\\2(7 - x) = 3x - 1\\14 - 2x = 3x - 1\\x = 15

From (a) we get y = 7 - x = 7 - 15 = -8

PART B:

Here the system of equations are -x + 4y = 17........(a) and 3x - 5y = -30.........(b)

From (a) we get, x = 4y - 17

Putting the above value of x in (b) we get, 3x - 5y = -30\\3(4y - 17) - 5y = -30\\12y - 51 - 5y = -30\\7y = 21\\y = 3

Hence, x = 4y - 17 = 12 - 17 = -5

3 0
3 years ago
/// WORTH 70 points /// ASAP ////
belka [17]

A community is developing plans for a pool and hot tub. The community plans to form a swim team, so the pool must be built to certain dimensions. Answer the questions to identify possible dimensions of the deck around the pool and hot tub.


Part I: The dimensions of the pool are to be 25 yards by 9 yards. The deck will be the same width on all sides of the pool. Including the deck, the total pool area has a length of (x + 25) yards, and a width of (x + 9) yards.

Write an equation representing the total area of the pool and the pool deck. Use y to represent the total area. Hint: The area of a rectangle is length times width. (1 point)

y = (x+25)(x+9)


Rewrite the area equation in standard form. Hint: Use the FOIL method. (1 point)


y = x^2 + 9x + 25x + 9(25)


y = x^2 +34x + 225


Rewrite the equation from Part b in vertex form by completing the square. Hint: Move the constant to the other side, add to each side, rewrite the right side as a perfect square trinomial, and finally, isolate y. (4 points: 1 point for each step in the hint)


y-225 = x^2 +34x


y-225 + 17^2 = x^2 +34x + 17^2


y-225 + 289 = (x+17)^2


y = (x+17)^2 - 64


What is the vertex of the parabola? What are the x- and y-intercepts? Hint: Use your answer from Part a to identify the x-intercepts. Use your answer from Part b to identify the y-intercept. Use your answer from Part c to identify the vertex. (4 points: 1 point for each coordinate point)

The vertex is where the squared term is zero, x=-17 , y =-64, (-17,-64)


The y intercept is y at x=0, so (0,225)


The x intercepts are the zeros; so at x=-25 and x=-9, aka (-25,0), (-9,0)


Graph the parabola. Use the key features of the graph that you identified in Part d. (3 points)


[Plot the points we generated and connect the dots. I'll leave the graphing to you]

In this problem, only positive values of x make sense. Why? (1 point)

<em>x</em> is the width of the pool edge; it must be positive.


What point on your graph shows a total area that includes the pool but not the pool deck? (1 point)


x=0, y=225 i.e. (0,225)



The community decided on a pool area that adds 6 yards of pool deck to both the length and the width of the pool. What is the total area of the pool and deck when x = 6 yards? (2 points)


(9+6)(25+6)=15(31)=465



Part II: A square hot tub will be placed in the center of an enclosed area near the pool. Each side of the hot tub measures 6 feet. It will be surrounded by x feet of deck on each side. The enclosed space is also square and has an area of 169 square feet. Find the width of the deck space around the hot tub, x.

Step 1: Write an equation for the area of the enclosed space in the form y = (side length)2. Hint: Don't forget to add x to each side of the hot tub. (1 point)



y=(x+6)(x+6)=(x+6)^2



Step 2: Substitute the area of the enclosed space for y in your equation. (1 point)


169 = (x+6)^2


Step 3: Solve your equation from Part b for x. (3 points)


x + 6 = \pm \sqrt{169}


x = -6&#10; \pm 13


x= 7 \quad \textrm{ or } \quad x= -19


Step 4: What is the width of the deck around the hot tub? Hint: One of the answers from Part c is not reasonable. (1 point)


Only the positive root works,


x=7 feet


5 0
3 years ago
Explain why 1.55 centimeters is a reasonable answer for the difference in the wingspans of the two butterflies
melamori03 [73]
The difference is referring to subtraction, so the question was most likely something like how much longer is this butterflies wings than this ones. so 4.55 might be one of the lengths and 3 might be the other, so 4.55 - 3 is 1.55.
4 0
3 years ago
PLEASE HELP AND BE CORRECT
Sergio [31]

(b⁷/4⁵)⁻³

= (4⁵/b⁷)³

= 4¹⁵/b²¹

Therefore answer is option b

Must click thanks and mark brainliest

3 0
3 years ago
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