Answer:
CaBr2 is a colorless solid and the charge on Calcium is +2
Explanation:
CaBr2 is a colorless solid at room temperature.
Other properties include -
a) It is a crystalline solid
b) Melting point of 765°C.
c) It is deliquescent
d) Soluble in water and absolute alcohol.
The charge of Br is -1. Here two atoms of Br attaches with one atom of calcium. Hence the charge of calcium is +2
Answer:
a. 1.23 V
b. No maximum
Explanation:
Required:
a. Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have?
b. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have?
The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.
E°cell = E°red, cat - E°red, an
If E°cell must be at least 1.10 V (E°cell > 1.10 V),
E°red, cat - E°red, an > 1.10 V
E°red, cat - 0.13V > 1.10 V
E°red, cat > 1.23 V
The minimum standard reduction potential is 1.23 V while there is no maximum standard reduction potential.
So what are u asking............????????
Answer:
The first thing we have to do is change and state all the units so that we can use our ideal gas law equation (
).
650 mmHg is a pressure unit, we have to convert this to kiloPascals. We know that 760 mmHg gives us 101 kPa.
P = 86kPa
T = 15°C + 273K = 288K
R (Gas constant) = 8.31 kj/mol
Molar mass of Ammonia (
) = (1 x 3) + (14) = 17g/mol
n (moles) = 
3.34 mol
V = ?
Rearrange the equation to solve for Volume:
Substitute the values inside:
V = 
<u>Therefore 93 L of volume is occupied by the ammonia gas.</u>
<u></u>
Answer:
D
Explanation:
PV =nRT
So V and T are inversely proportional
