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olga2289 [7]
3 years ago
10

A footballer kicks a ball at an angle of 45° with the horizontal. If the ball was in the air

Physics
1 answer:
Naily [24]3 years ago
3 0

Answer:

HOPE THIS ANSWER WILL HELP YOU

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calculate the work done by 2N force directed at 30 degree to the vertical to move a 500g box a horizontal distance of 400 cm acr
sattari [20]

Answer:

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Explanation:

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3 0
3 years ago
What is Br charge after it gains an electron?
sergeinik [125]

Im not 100% sure but i think its bromine.

Hope this helps ^_^

4 0
3 years ago
Consider the following list of numbers. 129, 685, 125, 511, 601, 52, 46 The height of a binary search tree is the maximum number
NemiM [27]

Answer:

The height of the tree is three (3) deep

Explanation:

It's 3 deep

Under 129, comes 125 and 685;

Under 125, comes 52 : Under 685, comes 511;

Under 52, comes 46 : Under 511, is 601.

This is illustrated below.

129

∧

125,685

|,|

52,511

|,|

46,601

5 0
3 years ago
Which of the following is an incorrect statement of one of newtons laws of motion?
weqwewe [10]

Explanation:

The newton's laws of motion are:

First law:

  "A body will remain in its state of rest or of uniform motion along a path unless it is acted upon by an external force. ".

This is popularly called the law of inertia.

Second law:

 "the acceleration of a body is produced by a net force that is inversely proportional to the mass of the body".

Third law:

  "action and reaction forces are equal and opposite in direction".

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

5 0
3 years ago
A student, who weighs 720N, is standing on a bathroom scale and riding an elevator that is moving downwards with a speed that is
jasenka [17]

Answer:

1) The mass of the student is approximately 73.39 kg

2) The net force on the student is approximately 947.523 N

3) The value the scale will read is approximately 96.59 kg

Explanation:

The given parameters are;

The weight of the student = 720 N

The speed at which the elevator is decreasing = 3.1 m/s²

1) The weight of the student = The mass of the student × The acceleration due to gravity

The acceleration due to gravity is a constant = 9.81 m/s²

Substituting the known values gives;

720 N = The mass of the student × 9.81 m/s²

∴ The mass of the student = 720 N/(9.81 m/s²) ≈ 73.39 kg

2) The forces acting on the student are;

i) The force of gravity which is the weight of the student acting downwards

ii) The inertia force of the slowing elevator acting downwards in the same direction as the weight of the student

The net force, F_{net} = The weight of the student + The inertia force of the slowing elevator

∴ The net force, F_{net} = 720 N + 73.39 kg × 3.1 m/s² ≈ 947.523 N

3) The scale will read the mass of the student as follows;

Mass reading of student on the scale = Force on scale/9.81

∴ Mass reading of student on the scale = 947.523/9.81 ≈ 96.59 kg

The value the scale will read = 96.59 kg.

3 0
3 years ago
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