Answer:

Step-by-step explanation:

Hi!
In my opinion, the easiest way to solve a problem like this is to find the greatest common factor (GCF) of the numerator and denominator and then divide both numbers by the GCF.
So first we need to find the factors of 45 and 72 and find the factor that has the most value that the two numbers both have.
45: 1, 3, 5, 9, 15, and 45
72: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72
It looks like the GCF is 9. Now we have to divide 45 and 72 by 9.
45 ÷ 9 = 5
72 ÷ 9 = 8
So the correct answer should be:

Hope this helps :)
The first 3 are examples of the difference of 2 squares so you use the identity
a^2 - b^2 = (a + b)(a - b)
x^2 - 49 = 0
so (x + 7)(x - 7) = 0
so either x + 7 = 0 or x - 7 = 0
giving x = -7 and 7.
Number 7 reduces to 3x^2 =12, x^2 = 4 so x = +/- 2
Number 8 take out GCf (d) to give
d(d - 2) = 0 so d = 0 , 2
9 and 10 are more difficult to factor
you use the 'ac' method Google it to get more details
2x^2 - 5x + 2
multiply first coefficient by the constant at the end
that is 2 * 2 = 4
Now we want 2 numbers which when multiplied give + 4 and when added give - 5:- -1 and -4 seem promising so we write the equation as:-
2x^2 - 4x - x + 2 = 0
now factor by grouping
2x(x - 2) - 1(x - 2) = 0
(x - 2) is common so
(2x - 1)(x - 2) = 0
and 2x - 1 = 0 or x - 2 = 0 and now you can find x.
The last example is solved in the same way.
Answer:
check this out
Step-by-step explanation: