1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
koban [17]
2 years ago
11

if you drive your car at an average speed of 105km/h, how far (in km) will you go in 3hours 30minutes ?​

Physics
1 answer:
irinina [24]2 years ago
5 0

Hi ;-)

1 hour ⇒ 105 km

0,5 hour (30 minutes) ⇒ 105 km : 2 = 52,5 km

3 hours 30 minutes ⇒ 3 · 105 km + 52,5 km =

= 315 km + 52,5 km = <u>367,5 km</u>

You might be interested in
The chemical substances in food that help maintain our body are known as what?
rodikova [14]

Answer:

Nutrients

Explanation:

4 0
3 years ago
Read 2 more answers
Newton’s first law of motion was a giant leap forward in scientific thought during Newton’s time. Even today, the idea is someti
Vinvika [58]

Answer:

The heavier the load in a cart, the harder the cart is to turn.

5 0
3 years ago
Read 2 more answers
How can a 1kg ball have more kinetic energy than a 100kg ball? Explain both using words and by providing a numerical example
MariettaO [177]

1 kg ball can have more kinetic energy than a 100 kg ball as increase in velocity is having greater impact on K.E than increase in mass.

<u>Explanation</u>:

We know kinetic energy can be judged or calculated by two parameters only which is mass and velocity. As kinetic energy is directly proportional to the (velocity)^2 and increase in velocity leads to greater effect on translational Kinetic Energy. Here formula of Kinetic Energy suggests that doubling the mass will double its K.E but doubling velocity will quadruple its velocity:

\text { Kinetic Energy }=\frac{1}{2} m v^{2}

Better understood from numerical example as given:

If a man A having weight 50 kg run with speed 5 m/s and another man B having 100 kg weight run with 2.5 m / s. Which man will have more K.E?

This can be solved as follows:

\text { Kinetic Energy of } \mathrm{A}=\frac{1}{2} 50 \times 5^{2}=625 \mathrm{J}

\text { Kinetic Energy bf } \mathrm{B}=\frac{1}{2} 100 \times 2.5^{2}=312.5 \mathrm{J}

It shows that man A will have more K.E.

Hence 1 kg ball can have more K.E than 100 kg ball by doubling velocity.

4 0
2 years ago
Many planets in our solar system (Saturn, Uranus, Neptune) have rings. If these rings are made of chunks of debris, why do they
Liono4ka [1.6K]
Generally, rings form from moons, asteroids, or comets that have disintegrated due to a collision or because they got too close to their planet (Roche Limit). ... Most of the debris, however, will not have enough energy to overcome the planet's gravity and will remain in orbit around the planet.
5 0
3 years ago
A bond between two copper atoms would be a<br> bond? *
mihalych1998 [28]
A metallic bond would be formed
8 0
2 years ago
Read 2 more answers
Other questions:
  • Which is the best procedure to make a permanent magnet?
    9·2 answers
  • Gold is used to make a super thin layer on the visors of astronauts' helmets because of which property in particular?
    6·1 answer
  • A proton is at the origin. One electron is at the point (2m, 4m)
    8·1 answer
  • Showing how a projectile motion is parabolic​
    13·1 answer
  • How is a driver supposed to act?
    12·2 answers
  • ANY help with answering ANY of the questions would be greatly appreciated. I don't understand physics at all.
    5·1 answer
  • Water is being boiled in an open kettle that has a 0.52-cm-thick circular aluminum bottom with a radius of 12.0 cm. If the water
    6·1 answer
  • If a wave is traveling at 600 m/s and it's wavelength is 50 m, what is the frequency of the wave?
    14·1 answer
  • Michelle recently started selling her invention: A bed that looks like it floats in mid-air. The bed is actually suspended by ma
    10·1 answer
  • Formula for deriving initial temperature in linear expansivity​
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!