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Dmitry [639]
3 years ago
14

A 1.000 g sample of nitrogen combined with a 0.0720 g sample of hydrogen to form N2H2. What compound is formed if 1.000 g of nit

rogen combines with 0.2160 g of hydrogen?
N2H6 NH3 NH4+ N4H4
Chemistry
1 answer:
bazaltina [42]3 years ago
4 0

Answer:

N₂H₆

Explanation:

A 1.000 g sample of nitrogen combined with a 0.0720 g sample of hydrogen to form N₂H₂ .

1.000 g of nitrogen combines with 0.2160 g of hydrogen in the next compound .

In this compound the component of nitrogen remains the same but the component of hydrogen becomes .2160 / .0720 = 3 times .

Hence component of hydrogen in the new compound will change from

H2 to H6 .

Hence the chemical formula of new compound will be

N₂H₆ .

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7. A 2.0 L container had 0.40 mol of He(g) and 0.60 mol of Ar(g) at 25°C.
Finger [1]

Answer:

a) Ek Ar > Ek He

b) v Ar < v He

c) If v Ar = 431 m/s ⇒ v He = 1710.44 m/s

d) Pt = 12.218 atm

e) P He = 4.887 atm and P Ar = 7.33 atm

Explanation:

container:

∴ V = 2.0 L

∴ n He = 0.4 mol

∴ n Ar = 0.6 mol

∴ T = 25°C ≅ 298 K

a) Internal energy (U) :

∴ U = Ek + Ep = kinetic energy + potential energy

∴ Ep: the potential interaction energy is neglected, assuming ideal gas mixture

⇒ U = Ek = N(1/2mv²)= 3/2 NKT

∴ N = nNo ....number of moleculas

∴ K = 1.380 E-23 J/K....Boltzmann's constant

∴ No = 6.022 E23 molec/mol....Avogadro's number

for He:

⇒ N = (0.4)(6.022 E23) = 2.4088 E23 molec

⇒ Ek = (3/2)(2.4088 E23)(1.380 E-23 J/K)(298) = 1485.892 J

for Ar:

⇒ N = (0.6)(6.022 E23) = 3.6132 E 23 molec

⇒ Ek = (3/2)(3.6132 E23)(1.380 E-23 J/K)(298) = 2228.838 J

** Ar gas has a greater average kinetic energy

b) He:

∴ N(1/2)mv² = (3/2)NKT

⇒ mv² = 3KT

⇒ v² = 3KT/m

⇒ v = √3KT/m

∴ m He = (0.4 mol)(4.0026 g/mol) = 1.601 g He = 1.601 E-3 Kg He

⇒ v = √(3(1.380 E-23)(298)/(1.601 E-3)) = 2.776 E-9 m/s He

Ar:

∴ m Ar = (0.6)(39.948 g/mol) = 23.969 g = 0.0239 Kg Ar

⇒ v = 6.99 E-10 m/s

** v Ar < v He

c) r = V Ar / v He = (6.99 E-10 m/s)/(2.776 E-9 m/s) = 0.252

∴ If v Ar = 431 m/s

⇒ v He = v Ar/0.252 = 431 m/s / 0.252 = 1710.44 m/s

d) Pt = ntRT / V

∴ nt = 0.4 + 0.6 = 1 mol

⇒ Pt = (1mol)(0.082 atm.L/K.mol)(298 K)/(2.00 L) = 12.218 atm

e) P He = nRT/V = (0.4)(0.082)(298)/2 = 4.8872 atm

⇒ P Ar = Pt - PHe = 12.218 - 4.8872 = 7.33 atm

3 0
2 years ago
2.What two factors must be held constant for density to be a constant ratio?
irina1246 [14]

Answer:

Temperature and Pressure

Explanation:

Temperature and pressure cause change in volume.

So any change in volume will alter the ratio of density as given by equation of density.

Density = mass/ volume

Change in volume will alter the ratio.

Kindly mark it branliest if the answer is little bit satisfying.

6 0
2 years ago
Read 2 more answers
How many of the zeros in the measurement 0.050060 are significant
Feliz [49]
I think 3 of them are its been 1 half years since ive done this i dont take chemistry anymore
6 0
2 years ago
Read 2 more answers
2H2S + 3O2 → 2SO2 + 2H2O<br><br><br>1. For every 10.0 g of H2S how many moles of SO2 are formed?
Veseljchak [2.6K]

Answer:10

Explanation:

7 0
2 years ago
Seaweed attached to rocks in the ocean performs photosynthesis underwater. Which statement best explains how some seaweed can su
tia_tia [17]

Answer:

It can use a small amount of sunlight for photosynthesis

Explanation:

Seaweeds are a group of marine plants/algae that grow attached to rocks underwater. However, despite their depth underwater, they still perform photosynthesis, which is a process that requires energy from sunlight.

Seaweeds are able to perform photosynthesis underwater because they are efficient users of sunlight energy. Hence, they require only a small amount of sunlight that penetrates the ocean to perform photosynthesis.

8 0
2 years ago
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