Answer:
4sqrt(3)
Step-by-step explanation:
If the triangle is equilateral, the hypotenuse is 2x
We can use the Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
x^2 + 12^2 = (2x)^2
x^2 + 144 = 4x^2
144 = 4x^2 -x^2
144 = 3x^2
48 = x^2
Taking the square root of each side
sqrt(48) = sqrt(x^2)
sqrt(16*3) = x
4 sqrt(3) =x
There are two circles with center A and D. The tangent line touches both point B and C. The given measurements are enough to solve for the missing value and the solution is shown below:
AB=9
BC=26
DC=8
Solve for the measurement of AC which the hypotenuse of legs AB and BC by Pythagorean theorem:
c²=a²+b²
c²=9²+26²
c=AC=27.51
Solve for angle of A
sin A=26/27.51
A=70.93°
Finally, we solve for the length of AD using SOH
sin 70.93°=AD/27.51
AD=26
The answer is 26.
The answer is -2/5 because you have to multiply the fractions in late that first and the then divide from left to right because left is always first.
