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Vlada [557]
2 years ago
11

The density of gold is 19.3 g/cm3, and the density of iron pyrite is 5.02 g/cm3. What substance do you think you found?

Chemistry
1 answer:
Harrizon [31]2 years ago
4 0

Answer:

Step 1

1 of 2

V = m / D; V (nugget of gold) = 50 g / 5.0 g / cm 3 = 10 cm3; V (nugget of iron pyrite) = 50 g / 19 g / cm3 = 2.63 cm 3

Result

2 of 2

Due to these results you can conclude that nugget of gold which volume is 10 cm3 is bigger than volume of nugget of iron pyrite which is 2.63 cm3.

Explanation:

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More on stoichiometric calculations can be found here: brainly.com/question/13384700

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