This problem uses the relationship between Kb and the the dissociation constants which is expressed as Kw = KaKb. Calculations are as follows:
<span>
Kb = KaKb
</span><span>1.00 x 10^-14 = 7.2 x 10^-4(x)
</span><span>x = 1.39 x 10^-11
</span><span>
We now need to calculate the [OH¯] using the Kb expression:
</span>1.39 x 10^-11 = x^2 / (0.30 - x)
<span>
The denominator can be neglected. </span><span>Thus, x is 3.73 x 10^-6.
</span><span>
pOH = -log 3.73 x 10^-6 = 5.43
p</span><span>H = 14-5.43 = 8.57</span>
<span>Evaporation is the process of atoms or molecules in a liquid, or solid state (depending on the state of the substance sublimes) gains enough energy to become gaseous. </span>
N=3^K-1 I really don't know how to explain it but that's the formula <span />
The crystals start to appear show that crystallization has just occurred.
<h3>What is crystallization?</h3>
Crystallization refers to the process by which a solid separates from the solution. Crystallization can be induced by;
- Scratching the vessel
- Adding some seed crystals to the solution.
Hence, when you take a metal spatula and scratch the side of the glass vessel that contains this cooled solution, and crystals start to appear, crystallization has just occurred.
Learn more about crystallization: brainly.com/question/816377