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3 years ago

Convert the following:

Chemistry

2 answers:

Gwar [14]3 years ago

5 0

Answer:

1. 254 milli

2. 5.3 centi

Explanation:

254 milli = 25.4 centi

53 milli = 5.3 centi

jolli1 [7]3 years ago

4 0

25.5 cm = 254 mm
53 mm = 5.3 cm

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Give three examples of environmental, industrial and bio-chemistry.

JulsSmile [24]

Three examples of environmental, industrial and bio-chemistry are listed below:

Environmental chemistry: Contamination, Atmospheric Deposition, and Soil Pollution.
industrial chemistry: industrial inorganic chemicals, industrial organic chemicals, and agricultural chemicals
bio-chemistry: genetic, immunology, and enzymology

<h3>Meaning of Chemistry</h3>

Chemistry can be defined as a branch of science which is concerned with the substances matter is composed of, their properties and reactions,

Chemistry also deals with the use of such reactions to form new substances.

In conclusion, Three examples of environmental, industrial and bio-chemistry are listed anove

Learn more about chemistry: brainly.com/question/24419453

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4 0

2 years ago

How do the mass and height of an object affect the gravitational potential energy?

marin [14]

Answer:

B. mass and height have the same effect on gravitational potential energy.

Explanation:

Both mass and height have the same effect on the gravitational potential energy of body.

Gravitational potential energy is the energy of a body due to that of another body. It usually the energy at rest in a body.

It is mathematically expressed as;

G.P.E = m x g x h

m is the mass

g is the acceleration due to gravity

h is the height

We see that both the height and mass are directly proportional to the gravitational potential energy and as such, they have the same effect.

5 0

3 years ago

What is the answer?

Dmitry_Shevchenko [17]

as a heterogeneous mixture

Explanation:

because I just know that it is

6 0

4 years ago

This decomposition is first order with respect to phosphine, and has a half‑life of 35.0 s at 953 K. Calculate the partial press

Solnce55 [7]

Answer:

0.57 atm

Explanation:

When a a reaction is first order, we have from calculus the following relation:

ln[A]t/[A]₀ = - kt

where [A]t is the concentration of A ( phosphine in this case ) after a time, t

[A]₀ is the initial concentration of A

k is the rate constant, and

t is the time

We also know that for a first order reaction

k = 0.693/ t 1/2

wnere t 1/2 is the half-life.

This equation is derived for the case when A]t/= 1/2 x [A]₀ which occurs at the half-life.

Thus, lets first find k from the half life time, and then solve for t = 70.5 s

k = 0.693 / 35.0 s = 0.0198 s⁻¹

ln [ PH₃ ]t / [ PH₃]₀ = - kt

from the ideal gas law we know pV = nRT, so the volumes cancel:

ln (pPH₃ )t / p(PH₃)₀ = - kt

taking inverse log to both sides of the equation:

(pPH₃ )t / p(PH₃)₀ = - kt

thus:

(pPH₃ )t = 2.29 atm x e^(- 0.0198 s⁻¹ x 70.5 s ) = 0.57 atm

3 0

3 years ago

An airplane travels 2100 km at 1000km/hE. It encounters a wind and slows to 800 km/h E for the next 1300 km. What is the average

Deffense [45]

Answer:

The average velocity of the airplane for this trip is 1684.21 km/h

Explanation:

Average velocity is the rate of change of displacement with time. That is,

Average velocity = $\frac{Displacement }{Change in time}$ = Δx / Δt = $\frac{x2 - x1}{t2 - t1}$

Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.

From,

Velocity = $\frac{Distance traveled}{Time taken}$

Time = $\frac{Distance traveled}{Velocity}$

Therefore, Time = $\frac{2100km }{1000km/h}$

Time = 2.1h

This is the time taken before the airplane encounters a wind.

Hence, t1 = 2.1h

Now, For the time taken by the airplane when it encounters a wind

Also from,

Velocity = $\frac{Distance traveled}{Time taken}$

Time = $\frac{Distance traveled}{Velocity}$

Therefore, Time = $\frac{1300km }{800km/h}$

Time = 1.625h

Hence, t2 = 1.625h

Now, to calculate the average velocity

Average velocity = $\frac{x2 - x1}{t2 - t1}$

x1= 2100, x2= 1300, t1= 2.1h and t2= 1.625h

Hence, Average velocity = $\frac{1300 - 2100}{1.625 - 2.1}$

Average velocity = 1684.21 km/h

7 0

3 years ago