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3 years ago

In a neutral atom the number of electrons equals the number of what part of what other part

Physics

1 answer:

koban [17]3 years ago

3 0

Protons

Explanation:

In a neutral atom, the number of electrons equals the number of protons in the atom.

Electrons are the negatively charge particles in an atom
Protons carry positive charge.
Neutrons do not carry any charges.

Protons and neutrons are contained in the nucleus of an atom they determine the mass number of the atom.

In a neutral atom, the number of protons and electrons must be the same.

A charge atom called an ion is one that has lost or gained electrons.

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Cations brainly.com/question/8698247

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A well hole having a diameter of 5 cm is to be cut into the earth to a depth of 75 m. Determine the total work (in joules) requi

guapka [62]

Answer:

total work is 99.138 kJ

Explanation:

given data

diameter = 5 cm

depth = 75 m

density = 1830 kg/m³

to find out

the total work

solution

we know mass of volume is

volume = $\frac{\pi}{4} d^2 dx$

volume = $\frac{\pi}{4} d^2 1830 dx$

work required to rise the mass to the height of x m

dw = $\frac{\pi}{4} d^2 1830$ gx dx

so total work is integrate it with 0 to 75

w = $\int\limits^{75}_{0} {\frac{\pi}{4} d^2 1830 gx dx}$

w = $\frac{\pi}{4}$ × 0.05² × 1830× 9.81× $(\frac{x^2}{2})^{75}_0$

w = 99138.53 J

so total work is 99.138 kJ

6 0

2 years ago

When a 20-V emf is placed across two resistors in series, a current of 2.0 A is present in each of the resistors. When the same

ehidna [41]

Answer:

7.24 ohm

Explanation:

Let R1 and R2 are resistance of two resistors.

Emf=E=20 V

Current,I=2 A

Current,I'=10 A

We have to find the magnitude of the greater of the two resistances.

In series

$R=R_1+R_2$

$V=IR$

By using the formula

$20=2(R_1+R_2)$

$R_1+R_2=\frac{20}{2}=10$ ...(1)

In parallel

$\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}$

$\frac{1}{R}=\frac{R_2+R_1}{R_1R_2}$

$R=\frac{R_1R_2}{R_1+R_2}$

$20=10(\frac{R_1R_2}{R_1+R_2}$

$2=\frac{R_1R_2}{10}$

$R_1R_2=20$

$R_2=\frac{20}{R_1}$

Substitute the value

$\frac{20}{R_1}+R_1=10$

$R^2_1+20=10R_1$

$R^2_1-10R_1+20=0$

$R_1=\frac{10\pm\sqrt{(-10)^2-4(20)}}{2}$

By using quadratic formula

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$R_1=\frac{10\pm 2\sqrt 5}{2}$

$R_1=\frac{10+2\sqrt 5}{2}=5+\sqrt 5=7.24 ohm$

$R_1=\frac{10-2\sqrt 5}{2}=2.76 ohm$

Substitute the value

$R_2=\frac{20}{7.24}=2.76 ohm$

$R_2=\frac{20}{2.76}=7.24 ohm$

Hence, the magnitude of the greater of the two resistance=7.24 ohm

8 0

3 years ago

Read 2 more answers

A 4.3 kg steel ball and 6.5 m cord of negligible mass make up a simple pendulum that can pivot without friction about the point

Alekssandra [29.7K]

Answer

given,

mass of steel ball, M = 4.3 kg

length of the chord, L = 6.5 m

mass of the block, m = 4.3 Kg

coefficient of friction, μ = 0.9

acceleration due to gravity, g = 9.81 m/s²

here the potential energy of the bob is converted into kinetic energy

$m g L = \dfrac{1}{2} mv^2$

$v= \sqrt{2gL}$

$v= \sqrt{2\times 9.8\times 6.5}$

v = 11.29 m/s

As the collision is elastic the velocity of the block is same as that of bob.

now,

work done by the friction force = kinetic energy of the block

$f . d = \dfrac{1}{2} mv^2$

$\mu m g. d = \dfrac{1}{2} mv^2$

$d=\dfrac{v^2}{2\mu g}$

$d=\dfrac{11.29^2}{2\times 0.9 \times 9.8}$

d = 7.23 m

the distance traveled by the block will be equal to 7.23 m.

8 0

2 years ago

In which place moutain or terai,the value of g is more and why?

PolarNik [594]

Answer:

the radius of the earth in himalayan region is greater than terai reagion. therefore, the value of 'g' at the poles is greater than the value of g at the equator. 12

Explanation:

plz mark as brainlist thx :)

6 0

3 years ago

A complete path through which charge can flow is an electric what?

grigory [225]

<span>A complete path through which charge can flow is an "Electric Circuit"

Hope this helps!</span>

5 0

3 years ago

Read 2 more answers