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labwork [276]
2 years ago
14

If 1 m = 100 cm , then how many cm^2 are there in a m^2 ?? please hel[p

Physics
2 answers:
maw [93]2 years ago
7 0

Answer:if 1 m = 100 cm then there should be 200 cm in m^2

Explanation:

eimsori [14]2 years ago
6 0
200 cm :))))))))))))))))))
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Answer:

A. Power = Work / Time

Explanation:

Power is the amount of work done over time, or rather the rate of work, which is given by the unit of watts (W). Since work is defined by Force * Displacement, we can also say Power = Force * Displacement / Time.

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Ejercicio 1: Un cuerpo gira en un círculo de 8cm de diámetro con una rapidez constante
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Answer:

Exercise 1;

The centripetal acceleration is approximately 94.52 m/s²

Explanation:

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2 years ago
A 60-W, 120-V light bulb and a 200-W, 120-V light bulb are connected in series across a 240-V line. Assume that the resistance o
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A. 0.77 A

Using the relationship:

P=\frac{V^2}{R}

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R_1=\frac{V^2}{P}=\frac{(120 V)^2}{60 W}=240 \Omega

For the second light bulb, P = 200 W and V = 120 V, so the resistance is

R_1=\frac{V^2}{P}=\frac{(120 V)^2}{200 W}=72 \Omega

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R=R_1 + R_2 = 240 \Omega + 72 \Omega =312 \Omega

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So we can find the current through the two bulbs by using Ohm's law:

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The power dissipated in the first bulb is given by:

P_1=I^2 R_1

where

I = 0.77 A is the current

R_1 = 240 \Omega is the resistance of the bulb

Substituting numbers, we get

P_1 = (0.77 A)^2 (240 \Omega)=142.3 W

C. 42.7 W

The power dissipated in the second bulb is given by:

P_2=I^2 R_2

where

I = 0.77 A is the current

R_2 = 72 \Omega is the resistance of the bulb

Substituting numbers, we get

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E is the amount of energy dissipated

t is the time interval

From part B and C we see that the 60 W bulb dissipates more power (142.3 W) than the 200-W bulb (42.7 W). This means that the first bulb dissipates energy faster than the second bulb, so it also burns out faster.

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Explanation: Please see the attachments below

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Answer:

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