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dybincka [34]
3 years ago
12

The record distance in the sport of throwing cowpats is 81.1 m. This record toss was set by Steve Urner of the United States in

1981. Assuming the initial launch angle was 45° and neglecting air resistance, answer the following. (a) Determine the initial speed of the projectile. m/s
Physics
1 answer:
N76 [4]3 years ago
7 0

Answer:

28.2 m/s

Explanation:

The range of a projectile launched from the ground is given by:

d=\frac{v^2}{g}sin 2\theta

where

v is the initial speed

g = 9.8 m/s^2 is the acceleration of gravity

\theta is the angle at which the projectile is thrown

In this problem we have

d = 81.1 m is the range

\theta=45^{\circ} is the angle

Solving for v, we find the speed of the projectile:

v=\sqrt{\frac{dg}{sin 2 \theta}}=\sqrt{\frac{(81.1 m)(9.8 m/s^2)}{sin (2\cdot 45^{\circ})}}=28.2 m/s

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Answer:

The  coefficient of kinetic friction  \mu_k =  0.724

Explanation:

From the question we are told that

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Generally from the work-energy theorem we have that  

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Here N  is the normal force acting on the truck which is mathematically represented as

     \Delta KE is the change in kinetic energy which is mathematically represented as

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=>     \Delta KE =  0.5  *  m *  22.6^2

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