Answer:
1.Length is one of the four factors on which the wave frequency depends. So if the length of the string changes then there will be a change in the vibration of string. So in this case if the lengths are different then the wave frequency of both will be different.
2. Wave speed will be the same as it depends on tension and linear density of it.
3. Wavelength itself is find out by the length of string so it depends on length and it will vary with the lengths of strings.
Explanation:
Weight = (mass) x (acceleration of gravity).
When I calculate the weight of the 81.6 kg, the number I use for gravity
is 9.807 m/s². That gives a weight of 800.25 N, so I think that's where the
question got the crazy number of 81.6 kg ... whoever wrote the problem
wants the hay to weigh 800 N, and that's what I'll use for the weight.
The forces on the bale of hay are gravity: 800N downward, and the
guy on the truck with the pitchfork pulling upward on it with 850 N.
The net force on the bale is (850 - 800) = 50 N upward.
Use Newton's second law of motion: (Net force) = (mass) x (acceleration)
Divide each side by 'mass' :
Acceleration = (net force)/(mass)
On the hay wagon,
Acceleration = (50 N upward) / (81.6 kg) = <em>0.613 m/s² upward</em>
The correct answer for the question that is being presented above is this one: "Schmidt-Cassegrain focus." A focal arrangement that has a thin lens that the light passes through before traveling down the tube to the objective mirror is a Schmidt-Cassegrain focus.
Here are the following choices:
a. Cassegrain focus
b. Newtonian focus
c. Schmidt-Cassegrain focus
<span>d. Schmidt focus</span>
Answer:
T = 17649.03 N = 17.65 KN
Explanation:
The tension in the cable must be equal to the apparent weight of the passenger. For upward acceleration:
where,
T = Tension in cable = ?
= Apparent weight
m = mass = 1603 kg
g = acceleration due to gravity = 9.81 m/s²
a = acceleration of elevator = 1.2 m/s²
Therefore,
<u>T = 17649.03 N = 17.65 KN</u>
S= 343m/s
F=256Hz
WL= 343ms/256-1
WL=V/F
= 1.339844m
