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BartSMP [9]
3 years ago
12

1.020 please help!! Mark brainliest

Physics
1 answer:
Viktor [21]3 years ago
5 0

Answer:

0.0035 mg

Explanation:

1 mcg = 1e-3 mg

》35 mcg = 35×10^-3 mg

= 0.0035 mg

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A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total
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When it comes to this equation, I always stick to good ol' momma bears solutions! Tell that boy to put the rock down, rocks are dangerous!! From- MommaBoi101
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A 1.3-kg ball is attached to the end of a 0.8-m string to form a pendulum. This pendulum is released from rest with the string h
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Answer:

2.9 m/s

Explanation:

Momentum will be conserved

Speed of the ball just before collision is

v = √2gh = √(2(9.8)(0.8)) = 3.96 m/s

The initial momentum is 1.3(3.96) = 5.15 kg•m/s

The block takes away momentum of 0.6(2.2) = 1.32 kg•m/s

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3 years ago
A mercury barometer reads 745.0 mm on the roof of a building and 760.0 mm on the ground. Assuming a constant value of 1.29 kg/m3
Ipatiy [6.2K]

Answer:

The height of the building is 158.140 meters.

Explanation:

A barometer is system that helps measuring atmospheric pressure. Manometric pressure is the difference between total and atmospheric pressures. Manometric pressure difference is directly proportional to fluid density and height difference. That is:

\Delta P \propto \rho \cdot \Delta h

\Delta P = k \cdot \rho \cdot \Delta h

Where:

\Delta P - Manometric pressure difference, measured in kilopascals.

\rho - Fluid density, measured in kilograms per cubic meter.

\Delta h - Height difference, measured in meters.

Now, an equivalent height difference with a different fluid can be found by eliminating manometric pressure and proportionality constant:

\rho_{air} \cdot \Delta h_{air} = \rho_{Hg} \cdot \Delta h_{Hg}

\Delta h_{air} = \frac{\rho_{Hg}}{\rho_{air}} \cdot \Delta h_{Hg}

Where:

\Delta h_{air} - Height difference of the air column, measured in meters.

\Delta h_{Hg} - Height difference of the mercury column, measured in meters.

\rho_{air} - Density of air, measured in kilograms per cubic meter.

\rho_{Hg} - Density of mercury, measured in kilograms per cubic meter.

If \Delta h_{Hg} = 0.015\,m, \rho_{air} = 1.29\,\frac{kg}{m^{3}} and \rho_{Hg} = 13600\,\frac{kg}{m^{3}}, the height difference of the air column is:

\Delta h_{air} = \frac{13600\,\frac{kg}{m^{3}} }{1.29\,\frac{kg}{m^{3}} }\times (0.015\,m)

\Delta h_{air} = 158.140\,m

The height of the building is 158.140 meters.

5 0
3 years ago
Read 2 more answers
A technician places a fluid substance, with a refractive index of 1.61, between two horizontal panes of flat glass (each of whic
Ahat [919]

Answer:

the minimum thickness (in nm)  t = 102.5 nm

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t = thickness of the film

n = index of refraction = 1.61

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so we have the formula

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2 (1.61) t = (1) (330 x 10-9)

then...

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converting...

t = 102.5 nm

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Are Roots or Plant Making Cracks in The Concrete Chemical or Weathering?
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