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3 years ago

What is the formula for tetrabromine decafluoride

Chemistry

1 answer:

Lyrx [107]3 years ago

4 0

Answer:

$Br_{4}F_{10}$

The prefix "Tetra" implies 4 Bromine atoms. The prefix "Deca" implies 10 fluorine atoms.

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_Cuo +H, → _Cu + _H,0

Elena-2011 [213]

<h3>Answer:</h3>

CuO(s) + H₂(g) → Cu(s) + H₂O(l)

<h3>Explanation:</h3>

Assuming the reaction is the reduction of CuO by H₂
Then the balanced equation for the reaction is;

CuO(s) + H₂(g) → Cu(s) + H₂O(l)

The equation shows the reducing property of hydrogen gas, such that hydrogen reduces metal oxides such as copper(ii)oxide to the respective metals.
The law of conservation requires chemical equations to be balanced so as the mass of reactants will be equal to that of products.

In this case; there is 1 copper atom, 1 oxygen atom and 2 hydrogen atoms on both side of the equation and thus the equation is balanced.

3 0

2 years ago

As the randomness of a system increases, the entropy of the system:

aev [14]

Answer:

it most likely increases

6 0

2 years ago

at a certain pressure the density of superficial carbon dioxide is 0.469. what is the mass of a 25.0 mL sample of supercritical

Murrr4er [49]

Answer:

$\large \boxed{\text{11.7 g}}$

Explanation:

$\text{Mass} = \text{25.0 mL} \times \dfrac{\text{0.469 g}}{\text{1 mL}} = \textbf{11.7 g}\\\\\text{The mass of the carbon dioxide is $\large \boxed{\textbf{11.7 g}}$}$

7 0

2 years ago

CLIC 3. The blank is the central part of an atom.

lorasvet [3.4K]

Answer:

The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge). The outermost regions of the atom are called electron shells and contain the electrons (negatively charged).

6 0

2 years ago

A saturated solution is made by dissolving 0.327 g of a polypeptide (a substance formed by joining together in a chainlike fashi

faust18 [17]

Answer: The approximate molecular mass of the polypeptide is 856 g/mol

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

Or,

$\pi=i\times \frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution in L)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = 4.19 torr

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (polypeptide) = 0.327 g

Volume of solution = 1.70 L

R = Gas constant = $62.364\text{ L.torr }mol^{-1}K^{-1}$

T = temperature of the solution = $26^oC=[273+26]K=299K$

Putting values in above equation, we get:

$4.19torr=1\times \frac{0.327}{\text{Molar mass of solute}\times 1.70}\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 299K\\\\\text{molar mass of solute}=856g/mol$

Hence, the molar mass of the polypeptide is 856 g/mol

8 0

2 years ago