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Veronika [31]
2 years ago
15

Draw the structures of the aldol addition and condensation products of 3‑methylbutanal

Chemistry
1 answer:
Leona [35]2 years ago
6 0

Aldol condensation involves  two aldehydes or two ketones or an aldehyde and a ketone. The product of the reaction is shown in the image attached.

<h3>What is Aldol condensation?</h3>

Aldol condensation is a reaction that involves two aldehydes or two ketones or an aldehyde and a ketone. This reaction occurs at the carbonyl group as one of the carbonyl compounds is in the enolate form.

The product of the reaction is shown in the image attached. This gives the mechanism for the Aldol condensation of the compound 3‑methylbutanal.

Learn more about aldol condensation: brainly.com/question/9415260

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vladimir1956 [14]
The thing that governs whether a reaction is exothermic is the energy given out / used up to break / form the bonds in the reaction. 

<span>When two substances react, the bonds in those substances first break up, releasing energy, before re-forming in a different way, taking in energy. The nature of the bonds that are broken up and reformed determines whether more energy is given out (exothermic) or taken in (endothermic)</span>
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3 years ago
Ap chemistry how to determine if compound is ionic or molecular bqsed on formula
ludmilkaskok [199]
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3 years ago
A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit
Triss [41]

Answer:

The final pressure is approximately 0.78 atm

Explanation:

The original temperature of the gas, T₁ = 263.0 K

The final temperature of the gas, T₂ = 298.0 K

The original volume of the gas, V₁ = 24.0 liters

The final volume of the gas, V₂ = 35.0 liters

The original pressure of the gas, P₁ = 1.00 atm

Let P₂ represent the final pressure, we get;

\dfrac{P_1 \cdot V_1}{T_1} = \dfrac{P_2 \cdot V_2}{T_2}

P_2 = \dfrac{P_1 \cdot V_1 \cdot T_2}{T_1 \cdot V_2}

P_2 = \dfrac{1 \times 24.0 \times 298}{263.0 \times  35.0} = 0.776969038566

∴ The final pressure P₂ ≈ 0.78 atm.

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Answer:

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Sugar dissolving in warm water is chemical or phyiscal change
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