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Veronika [31]
2 years ago
15

Draw the structures of the aldol addition and condensation products of 3‑methylbutanal

Chemistry
1 answer:
Leona [35]2 years ago
6 0

Aldol condensation involves  two aldehydes or two ketones or an aldehyde and a ketone. The product of the reaction is shown in the image attached.

<h3>What is Aldol condensation?</h3>

Aldol condensation is a reaction that involves two aldehydes or two ketones or an aldehyde and a ketone. This reaction occurs at the carbonyl group as one of the carbonyl compounds is in the enolate form.

The product of the reaction is shown in the image attached. This gives the mechanism for the Aldol condensation of the compound 3‑methylbutanal.

Learn more about aldol condensation: brainly.com/question/9415260

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A student plots the magnetic field of a bar magnet using a compass the student centers the bar magnet in the middle of a piece o
olga55 [171]

The diagram best shows the magnetic field around the bar magnet is the diagram in option B.

<h3>What is the magnetic field?</h3>

The magnetic field refers to the region in space where the influence of a magnet can be felt. We know that strength of magnet can be seen by following the magnetic lines of force. The more the magnetic lines of force, the stronger the magnetic field especially when the line are packed closely together.

Looking at the diagrams of the magnetic lines of force, it must be recalled that the magnetic lines of force runs from the north pole to the south pole and not the other way round.  

Thus, the diagram best shows the magnetic field around the bar magnet is the diagram in option B.

Learn more about magnetic field:brainly.com/question/14848188

#SPJ1

4 0
2 years ago
I want someone he is good in chemistry
Over [174]

Answer:

<h2>.I can help you.....</h2>

Explanation:

<h2>am good at </h2>

moles

bonding

balancing equations

and set ups

8 0
3 years ago
A gas with a volume of 250 mL at a temperature of 293K is heated to 324K. What is the new volume of the gas?
Natalija [7]

Answer:

The new volume of the gas is 276.45 mL.

Explanation:

Charles's law indicates that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases.

Charles's law is a law that mathematically says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

\frac{V}{T} =k

Analyzing an initial state 1 and a final state 2, it is satisfied:

\frac{V1}{T1} =\frac{V2}{T2}

In this case:

  • V1= 250 mL
  • T1= 293 K
  • V2= ?
  • T2= 324 K

Replacing:

\frac{250 mL}{293 K} =\frac{V2}{324 K}

Solving:

V2=324 K*\frac{250 mL}{293 K}

V2= 276.45 mL

<em><u>The new volume of the gas is 276.45 mL.</u></em>

4 0
3 years ago
A student constructs a coffee cup calorimeter and places 50.0 mL of water into it. After a brief period of stabilization, the te
Grace [21]

Answer:

The calorimeter constant is  = 447 J/°C

Explanation:

The heat absorbed or released (Q) by water can be calculated with the following expression:

Q = c × m × ΔT

where,

c is the specific heat

m is the mass

ΔT is the change in temperature

The water that is initially in the calorimeter (w₁) absorbs heat while the water that is added (w₂) later releases heat. The calorimeter also absorbs heat.

The heat absorbed by the calorimeter (Q) can be calculated with the following expression:

Q = C × ΔT

where,

C is the calorimeter constant

The density of water is 1.00 g/mL so 50.0 mL = 50.0 g. The sum of the heat absorbed and the heat released is equal to zero (conservation of energy).

Qabs + Qrel = 0

Qabs = - Qrel

Qcal + Qw₁ = - Qw₂

Qcal = - (Qw₂ + Qw₁)

Ccal . ΔTcal = - (cw . mw₁ . ΔTw₁ + cw . mw₂ . ΔTw₂)

Ccal . (30.31°C - 22.6°C) = - [(4.184 J/g.°C) × 50.0 g × (30.31°C - 22.6°C) +  (4.184 J/g.°C) × 50.0 g × (30.31°C - 54.5°C)]

Ccal  = 447 J/°C

5 0
3 years ago
If it requires 48.3 milliliters of 0.55 molar nitric acid to neutralize 15.0 milliliters of barium hydroxide, solve for the mola
Gemiola [76]
First you have to moles so multiply .0483L X .55M= .026565 Multiply moles by mole ratio which is 1/2, so the moles becomes .013283 now molarity=moles/volume; divide .013283/.015L=.885533M significant figures and you final answer is 0.89M
8 0
3 years ago
Read 2 more answers
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