Draw the structures of the aldol addition and condensation products of 3‑methylbutanal
1 answer:
Aldol condensation involves two aldehydes or two ketones or an aldehyde and a ketone. The product of the reaction is shown in the image attached.
<h3>What is Aldol condensation?</h3>Aldol condensation is a reaction that involves two aldehydes or two ketones or an aldehyde and a ketone. This reaction occurs at the carbonyl group as one of the carbonyl compounds is in the enolate form.
The product of the reaction is shown in the image attached. This gives the mechanism for the Aldol condensation of the compound 3‑methylbutanal.
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Answer:
0.895 g/mL
Explanation:
Step 1: Given data
Mass of liquid Z (m): 2.763 lb
Volume of liquid Z (V): 5.93 cups
Step 2: Convert "m" to grams
We will use the relationship 1 lb = 453.59 g.
Step 3: Convert "V" to milliliters
We will use the relationship 1 cup = 236.59 mL.
Step 4: Calculate the density of the liquid Z
The density (ρ) of the liquid Z is equal to its mass divided by its volume.
When 1-Bromopropane is treated with methoxide it undergoes SN² Reaction. The product formed is Methyl Propyl Ether. This type of reaction is very important in synthesizing Asymmetric ethers. The alkoxides are oftenly generated by reacting Alcohols with sodium metal, which on elimination of Hydrogen gas produces corresponding alkoxide. The reaction of given statement is as follow,
