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Radda [10]
3 years ago
8

Which process is expected to have an increase in entropy?

Chemistry
1 answer:
olganol [36]3 years ago
4 0

Answer: Option (B) is the correct answer.

Explanation:

Degree of randomness of the molecules of a substance is known as entropy. More is the kinetic energy between the molecules of a substance more will be the degree of randomness.

Therefore, when a substance is present in a gaseous state then it has the maximum entropy. In liquid state, molecules are closer to each other so, there is less randomness between them.

On the other hand, in solid state molecules are much more closer to each other as they arr held by strong intermolecular forces of attraction. Therefore, they have very less entropy.

  • When liquid water is formed from gaseous hydrogen and oxygen molecules then gas is changing into liquid. So, there is decrease in entropy.
  • When N_{2}O_{4} decomposes then the reaction will be as follows.

            N_{2}O_{4} \rightarrow 2NO_{2}

Since, 1 mole is producing 2 moles. This means that degree of randomness is increasing as both the molecules are present in gaseous form.

  • In formation of a precipitate, aqueous solution is changing into solid state. Hence, degree of randomness is decreasing.
  • Rusting of iron also leads to the formation of solid as it forms Fe_{2}O_{3}.xH_{2}O.

Thus, we can conclude that decomposition of N_{2}O_{4} gas to NO_{2} gas is the process that is expected to have an increase in entropy.

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The Ki of an inhibitor is known as the inhibition constant.

The inhibition is a competitive inhibition as the Vmax is unchanged but Km changes.

Using the Michaelis-Menten equation for inhibition:

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Making Ki subject of the formula:

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Ki = 26.7 μM/{(2.5/1) - 1)

Ki = 53.4 μM

Therefore, the Inhibition constant, Ki of the inhibitor is 53.4 μM.

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The best and most correct answer among the choices provided by your question is the fourth choice.

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