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kipiarov [429]
3 years ago
14

15 points and brainliest to whoever helps me!

Physics
1 answer:
Juliette [100K]3 years ago
6 0

Answer:

The correct answer is false, a plant dying after being exposed to poison is not a physical change nor is it a physical property.

Explanation:

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8 The diagram shows four identical spheres placed between two wooden blocks on a ruler.
enyata [817]

The diameter of the sphere is 2cm.

<h3>How to calculate the diameter?</h3>

From the diagram, the first sphere on the ruler is at 4cn and the last sphere is at 12cm.

Therefore, the length will be:

= 12 - 4.

= 8cm

The diameter of one sphere will be:

= Length / 4

= 8/4

= 2

Therefore, the diameter of the sphere is 2cm.

Note that the second question wasn't found online.

Learn more about diameter on:

brainly.com/question/358744

#SPJ1

8 0
2 years ago
Why are peer reviews important?
Pavlova-9 [17]

Answer:

Peer reviews are important because individuals with similar background knowledge are used to review work to detect inaccuracies or deficiencies in the work.

Explanation:

Those individuals with similar educational and work background knowledge can more accurately review work since they have the required knowledge base for the subject.

7 0
3 years ago
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Light can be transmitted through long fiber optic strands because of
wariber [46]
Total internal reflection. Although I'm not 100%


3 0
3 years ago
Read 2 more answers
The tub of a washer goes into its spin cycle, starting from rest and gaining angular speed steadily for 7.00 s, at which time it
Keith_Richards [23]

Answer:

The no. of revolutions does the tub turn while it is in motion is = 52.51 revolutions

Explanation:

Given data

\omega_1 = 0

\omega_2 = 5 \frac{rev}{sec}

Time taken = 7 sec

(1). The angular acceleration is given by

\alpha = \frac{d \omega}{dt}

\alpha  = \frac{5}{7}

\alpha  = 0.714 \frac{rev}{s^{2} }

We know that from the equation of motion

\omega_2^{2} =  \omega_1^{2} + 2 \alpha \theta_1

5^{2} = 0 + 2 (0.714) \theta_1

\theta_1 = 17.5 \ rev  -------- (1)

(2). The angular acceleration is given by

\alpha = \frac{d \omega}{dt}

\alpha = - \frac{5}{14}

\alpha = - 0.357 \frac{rev}{s^{2} }

We know that from the equation of motion

\omega_2^{2} =  \omega_1^{2} + 2 \alpha \theta_2

0^{2} = 5^{2} + 2 (-0.357) \theta_2

\theta_2 = 35.01 rev  -------  (2)

Total no of revolution made by the machine is

\theta = \theta_1 + \theta_2

\theta = 17.5 + 35.01

\theta = 52.51 rev

Therefore the no. of revolutions does the tub turn while it is in motion is = 52.51  rev

8 0
3 years ago
A flat loop of wire consisting of a single turn ofcross-sectional area 7.90 cm2is perpendicular to a magnetic field that increas
Westkost [7]

To develop this problem, it is necessary to apply the concepts related to Faraday's law and Magnetic Flow, which is defined as the change that the magnetic field has in a given area. In other words

\Phi = BA Cos\theta

Where

B= Magnetic Field

A = Area

\theta = Angle between magnetic field lines and normal to the area

The differentiation of this value allows us to obtain in turn the induced emf or electromotive force.

In this case we have that the flat loop of wire is perpendicular to the magnetic field, therefore the angle is 0 degrees, since its magnetic field acts parallel to the area:

\theta = 0 then our expression can be written as

\Phi = BA

From the same value of the electromotive force we have to

\epsilon = -\frac{d\Phi}{dt}

Replacing we have

\epsilon = -A\frac{B}{dt}

Replacing with our values we have that

\epsilon = -(7.9*10^{-4}m)\frac{(3.5-0.5)}{0.1}

\epsilon = -0.0237V

Therefore the magnitude of the induced emf in the loop is 0.0237V

On the other hand we have that the current by Ohm's Law can be defined as

I = \frac{\epsilon}{R}

For the given value of the resistance and the previously found potential we have to

I = \frac{0.237}{1.3}

I= 0.0182A

6 0
3 years ago
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