Answer:
Volume of chlorine = 61.943 mL
Explanation:
Given:
Volume of the water in the Pool = 18,000 gal
also,
1 gal = 3785.412 mL
thus,
Volume of water in pool = 18,000 × 3785.412 = 68,137,470 mL
Density of water = 1.00 g/mL
Therefore,
The mass of water in the pool = Volume × Density
or
The mass of water in the pool = 68,137,470 mL × 1.00 g/mL = 68,137,470 g
in terms of million = 
or
= 68.13747 g
also,
1 g of chlorine is present per million grams of water
thus,
chlorine present is 68.13747 g
Now,
volume = 
or
Volume of chlorine = 
or
Volume of chlorine = 61.943 mL
It can form dipole-dipole interactions but that’s all
Put it in a beaker. Use a smaller beaker filled half way with ice and water and place in the larger one. It should be about an inch or two above the mixture. Heat over a Bunsen burner and the naphthalene will deposit on the bottom of smaller beaker.
And in this way, nephthalene be separated from the mixture of KBR and sand.
2.49 x 10^46 is the answer
The correct answer is letter a. distillation of a mixture. “Gasoline boils at a relatively low temperature (about 150°C). The kerosene is removed at around 200°C, followed by diesel oil at 300°C and fuel oil ataround 370°C," It is the process of DISTILLATION OF A MIXTURE.Here is the question.
<span>
What topic is the teacher most likely talking about?
a. distillation of a mixture
b. filtration of a pure substance
c.evaporation of a mixture
d. sorting of a pure substance</span>
