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3 years ago

What element has 4 valence electrons and 5 electron shells?

Chemistry

1 answer:

marta [7]3 years ago

8 0

Answer: Tin (Sn)

Explanation: The electron configuration for tin (Sn) is shown in the picture. It's last electrons are:

5s^2 4d^10 5p^2

The valence electrons are in the 5th electron shell and include 2 each in the 5s and 5p orbitals.

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How many moles of water are needed to react with 8.4 moles of NO2?

monitta

Answer:

2.8 moles

Explanation:

3 0

2 years ago

WHEN A SOCCER PLAYER KICKS A BALL, THE BALL ACCELRATES. EXPLAIN WHAT CAUSES THIS ACCELERATION IN TERMS OF FORCES?

Nana76 [90]

Answer:

When we kick the ball, the force we apply to it causes it to accelerate from a speed of 0 to a speed of dozens of kilometers per hour. When the ball is released from the foot, it begins to decelerate (negative acceleration) due to the force of friction that is exerted upon it (as we observed in the previous example).

Explanation:

5 0

4 years ago

The dissociation of calcium carbonate has an equilibrium constant of Kp= 1.20 at 800°C. CaCO3(s) ⇋ CaO(s) + CO2(g)

Fed [463]

Explanation:

(a) Formula that shows relation between $K_{c}$ and $K_{p}$ is as follows.

$K_c = K_p \times (RT)^{-\Delta n}$

Here, $\Delta n$ = 1

Putting the given values into the above formula as follows.

$K_c = K_p \times (RT)^{-\Delta n}$

= $1.20 \times (RT)^{-1}$

= $\frac{1.20}{0.0820 \times 1073}$

= 0.01316

(b) As the given reaction equation is as follows.

$CaCO_{3}(s) \rightleftharpoons CaO(s) + CO_{2}(g)$

As there is only one gas so ,

$p[CO_{2}] = K_{p}$ = 1.20

Therefore, pressure of $CO_{2}$ in the container is 1.20.

(c) Now, expression for $K_{c}$ for the given reaction equation is as follows.

$K_{c} = \frac{[CaO][CO_{2}]}{[CaCO_{3}]}$

= $\frac{x \times x}{(a - x)}$

= \frac{x^{2}}{(a - x)}[/tex]

where, a = initial conc. of $CaCO_{3}$

= $\frac{22.5}{100} \times 9.56$

= 0.023 M

0.0131 = $\frac{x^{2}}{0.023 - x}$

x = 0.017

Therefore, calculate the percentage of calcium carbonate remained as follows.

% of $CaCO_{3}$ remained = $(\frac{0.017}{0.023}) \times 100$

= 75.46%

Thus, the percentage of calcium carbonate remained is 75.46%.

3 0

4 years ago

When rubidium metal is exposed to air, two atoms of rubidium, Rb, combine with one atom

Eddi Din [679]

2.1653 g

Explanation:

The molar mass of Rubidium is;

85.468 g/mol

Therefore the moles of Rubidium that reacted with oxygen is;

1.98 / 85.468

= 0.0232 moles

If every two moles of Rubidium reacts with one mole of oxygen then the amount of oxygen consumed in the chemical reaction is;

0.5 * 0.0232

= 0.0116 moles

The molar mass of an oxygen atom is 16 g/mole. Then the amount of O in grams consumed is;

0.0116 * 16

=0.1853 g

The final weight of the Rubidium II Oxide is;

1.98 + 0.1853

= 2.1653 g

8 0

3 years ago

In a certain chemical process, water reacts with a compound, and the water is converted into another compound during the reactio

gtnhenbr [62]

Answer:

hydration reaction

Explanation:

The type of reaction would be hydration reaction.

<u>Hydration reaction generally involves a chemical reaction of water with another reactant and in which the water ends up being converted to another product entirely. </u>

A good example of hydration reaction is the reaction between alkene and water leading to the production of alcohol.

$CH_2=CH_2(g) + H_2O(g)$ ⇄ $CH_3CH_2OH(g)$

8 0

3 years ago

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