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Musya8 [376]
3 years ago
10

Which of the following plays a major role in creating surface currents?

Physics
2 answers:
Temka [501]3 years ago
5 0
A. Daily tides create surface currents
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maria [59]3 years ago
3 0
C. Earth's rotation I think.
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A stone is dropped from from rest at the top of a mine shaft. It takes 95 seconds for the stone to fall to the bottom of the min
Marianna [84]

Distance of fall from rest,
without air resistance              =  (1/2) (gravity) (time)²

                                             = (1/2) (9.8 m/s²) (95 sec)²

                                             =  (4.9 m/s²) (9,025 sec²)

                                             =        44,222.5 meters  .

The depth of the mine shaft is five times the height of Mt. Everest !


6 0
3 years ago
The temperature of a gas is _____.
kykrilka [37]
Directly proportional to pressure
8 0
3 years ago
Read 2 more answers
A girl rolls a ball up an incline and allows it to re- turn to her. For the angle and ball involved, the acceleration of the bal
zalisa [80]

Answer:

3.28 m

3.28 s

Explanation:

We can adopt a system of reference with an axis along the incline, the origin being at the position of the girl and the positive X axis going up slope.

Then we know that the ball is subject to a constant acceleration of 0.25*g (2.45 m/s^2) pointing down slope. Since the acceleration is constant we can use the equation for constant acceleration:

X(t) = X0 + V0 * t + 1/2 * a * t^2

X0 = 0

V0 = 4 m/s

a = -2.45 m/s^2 (because the acceleration is down slope)

Then:

X(t) = 4*t - 1.22*t^2

And the equation for speed is:

V(t) = V0 + a * t

V(t) = 4 - 2.45 * t

If we equate this to zero we can find the moment where it stops and begins rolling down, that will be the highest point:

0 = 4 - 2.45 * t

4 = 2.45 * t

t = 1.63 s

Replacing that time on the position equation:

X(1.63) = 4 * 1.63 - 1.22 * 1.63^2 = 3.28 m

To find the time it will take to return we equate the position equation to zero:

0 = 4 * t - 1.22 * t^2

Since this is a quadratic equation it will have to answers, one will be the moment the ball was released (t = 0), the other will eb the moment when it returns:

0 = t * (4 - 1.22*t)

t1 = 0

0 = 4 - 1.22*t2

1.22 * t2 = 4

t2 = 3.28 s

7 0
3 years ago
2.)
Oduvanchick [21]

Answer:

-22.7 m/s^2

Explanation:

This is a uniformly accelerated motion, so we can determine the deceleration of the car by using a suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the car in this problem,

u = 27.8 m/s

v = 0

s = 17 m

Solving for a, we find the acceleration:

a=\frac{v^2-u^2}{2s}=\frac{0-27.8^2}{2(17)}=-22.7 m/s^2

4 0
3 years ago
A large raindrop-the type that lands with a definite splat-has a mass of 0.0014 g and hits your roof at a speed of 8.1 m/s. a. W
DENIUS [597]

Answer

given,

mass of the drop, m = 0.0014 g

speed of the drop, u = 8.1 m/s

a) Change in momentum is equal to impulse

   final velocity of the drop, v = 0 m/s

   J = m ( v - u )

   J = 0.0014 x 10⁻³ x ( 0 - 8.1 )

   J = -1.134 x 10⁻⁵ kg.m/s

impulse of the roof = - J = 1.134 x 10⁻⁵ kg.m/s

b) time, t = 0.37 m s

   impact of force = ?

  we know

     J = F x t

   1.134 x 10⁻⁵ = F x 0.37 x 10⁻³

     F =  0.031 N

the magnitude of the force of the impact is equal to F =  0.031 N

5 0
3 years ago
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